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viva [34]
3 years ago
9

How do you find the length of an arc

Mathematics
1 answer:
marysya [2.9K]3 years ago
3 0
The total length around the circle = 2 pi r = 2*pi*16 = 32 pi 

Total degrees around the circle = 360 so 

length of the arc of measure 270  = 32 pi * 270/360 =  24 pi  units

or 75.40 units to the nearest hundredth
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In the 2014 - 2015 school year, the mean score on the critical reading of the SAT was 490 with a standard deviation of 102 for j
bonufazy [111]

<u>Answer:</u>

The Ranking Percentile is (B) 97.5%

<u>Explanation :</u>

To find the percentile rank we need to find the z- score. After finding the z-score match this value with the corresponding value in z-score table.

Formula to find the z-score

Z-score=\frac{\text { scored obtained - mean }(\mu)}{\text { standard deviation }(\sigma)}

Substituting the values in the above equation, we find

Z-score= \frac{(694-490)}{102}=2

So, the Z-score is +2

Now, the corresponding value of Z-score 2 in the table is 0.9772

or the percentile score is 97.72 ~ 97.5 .

3 0
3 years ago
What is 48 times 3 I'm giving y'all an easy chance for points answer is 144 I think
ch4aika [34]

Answer:

yup you are correct. The answer is 144 :)

Step-by-step explanation:

Also thx for the points!

3 0
3 years ago
Read 2 more answers
Armand ran the 100 yard dash in 17.18 seconds. Arturo's time has an 8 with a value 10 times the value of the 8 in Armand's time.
frosja888 [35]
8====D

He has a value of 64
4 0
3 years ago
3 (2x -1) = -2 (x +3)
Misha Larkins [42]

Answer:

x = 3/8 (but the fraction is negative.)

Decimal form if needed.

x = - 0.375

6 0
3 years ago
P1=(-1,3) and P2=(5,-1) <br><br> Find the distance from p1 to P2
LenaWriter [7]

Answer:

7.21

Step-by-step explanation:

Given that:

P1=(-1,3) and P2=(5,-1)

Distance between two points :

d = Sqrt[(x2 - x1)² + (y2 - y1)²]

x1 = - 1 ; y1 = 3

x2 = 5 ; y2 = - 1

d = Sqrt[(5 - (-1))² + ((-1) - 3)²]

d = Sqrt[(5 + 1)² + (-1 - 3)²]

d = sqrt[(6)^2 + (-4)^2]

d = sqrt(36 + 16)

d = sqrt(52)

d = 7.21

3 0
3 years ago
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