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kakasveta [241]
3 years ago
5

F(x) = (1.07)^x what does this function represent

Mathematics
1 answer:
Zanzabum3 years ago
3 0
B. Exponential decay of 7%
Hope I helped!!
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6. The functions off and g are defined by f(x) = 4x + 2 and g(x) = x². Calculate for:
likoan [24]

Answer:

\boxed{66}

Step-by-step explanation:

if \: the \: question \: is \: f[g(4)] \\ then \: at \: first \: solve \: for \: g(4) \\ g(4) =  {4}^{2}  \\ f[g(4)]  = 4( {4}^{2} ) + 2 \\ f[g(4)]  = 4(16) + 2 \\ f[g(4)]  =64 + 2 \\   f[g(4)]  =  \boxed{66}

3 0
3 years ago
The shape is a rectangle, will you please help me find the angle measures of 1,2 and 3?
Ulleksa [173]

Answer:

  ∠1 = ∠3 = 54°; ∠2 = 36°

Step-by-step explanation:

Each of the triangles is isosceles. Triangles opposite each other are congruent, so ∠2 is congruent to 36°.

∠2 and ∠3 are complementary, so ∠3 is 54°. Since ∠3 is congruent to ∠1, it, too, is 54°.

8 0
3 years ago
Can someone explain how to do #3?
dsp73

\displaysyle (\sqrt 2)^{3}=(2^{\frac{1}{2}})^3=2^{\frac{1}{2} \cdot 3}=2^{\frac{3}{2}}=\sqrt {2^3}=\sqrt 8

√8 is between 2 and 3, because 2²=4<8, but 3²=9>8. Also, our value is closer to 3 than to 2, so it is more than 2.5 and we have C and D options left.

Among these two numbers we find the one which is closer to √8.

C. 27=√729 ⇒ 2.7=√7.29

D. 28=√784 ⇒ <u>2.8=√7.84</u>

Hence our answer is D) 2.8

5 0
3 years ago
Read 2 more answers
kinata goes for swimming lesson every 5 days while wagos goes every 6 days. if both kinaata and wayos had swimming lesson togeth
diamong [38]
I think it’s either 4 or 20

5 x 4 =20

6 x 4 =20
4 0
3 years ago
Find the coordinates of the intersection of the diagonals of parallelogram GHJK with vertices G(0,2), H(4,2), J(3,0), and K(-1,0
zimovet [89]

Answer:

(1.5,1)

Step-by-step explanation:

The midpoint of G and H is at (2,2).

The midpoint if J and K is (1,0)

The midpoint of the two midpoints is (1.5,1)

You could also i.e. directly ask for the midpoint of H an K, OR, G and J, and you would get the same final result.

8 0
3 years ago
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