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lana [24]
4 years ago
13

What is the sum of the arithmetic series below?

Mathematics
1 answer:
Romashka [77]4 years ago
7 0
When we substitute the initial values of i, we find that the series is:
3, 5, 7, 9 ...
This means it is an arithmetic progression with the first term being 3 and the common difference being 2. We have to find the sum of the first 18 terms. Using the formula:

Sn = n/2[2a + (n - 1)d]
S₁₈ = 18/2[2(3) + (18 - 1)2]
S₁₈ = 360
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What is the difference between -131 and -87 on a number line
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44 because the absolute values are 131 and 87 and to find difference you subtract.

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Kareem saves his coins in a jar. 30% of the coins are pennies. if there are 24 pennies in the jar, how many coins does Kareem ha
oksian1 [2.3K]
30%=30/100=3/10

3/10 of all=pennies=24
divide by 3
1/10 of all=8
times 10
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80 coins she has
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4 years ago
Functions 1 and 2 below represent the position (y) of a particle over time (x). Which function is moving faster? Explain your An
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I am not sure about this one, but I’m pretty sure function 1 as 24 divided by 2 is 2, which makes (2,0) and function 1 has (0,2). The higher the line, the greater it is.
4 0
3 years ago
PLS HELP I WILL GIVE BRAINLYEST!!!!!!
KiRa [710]

Answer:

36 is the answer

Step-by-step explanation:

7 0
3 years ago
11. Twyla and Tony have a 30/5 balloon mortgage for $389,900 with a rate of 4.85%. How much will they pay in interest over the l
kykrilka [37]

Answer:

Explanation:

Twyla and Tony with a balloon mortgage of 30/5 will make constant payments over the space of 5 years and then complete the bulk balloon payment for 25 years remaining.

Given mortgage loan value of $389900

Interest rate of 4.85%

We are asked to calculate the interest over the life of the loan.

We will calculate interest by calculating constant payments over the period of 5 years before balloon payment is due and adding them together then subtracting the mortgage loan given $389900

Formula for constant payments :

A= P×r×r(1+r)^n/(1+r)^n-1

Where A= constant/monthly payments

r= interest rate on the mortgage loan

n= number of payments = 30×12= 360

P= mortgage loan given

A= $389900×0.0485×0.0485(1+0.0485)^360/(1+0.0485)^360-1

=$389900×0.0485×1231340.79/25388468.94

=$389900×0.0485×0.04850

A= $917.142

Payment for five years(with interest)= $917.142×60= $55028.52

Calculate balloon payment:

FV= PV(1+r)^n - P((1+r)^n-1/r)

Where FV= future value of balloon payment

PV= initial loan given

r= interest rate on loan

n= number of payments

P= monthly payments

Substitute:

FV= $389900(1+0.0485/12)^60-917.142((1+0.0485/12)^60-1/0.0485/12)

=$389900×1.2738-917.142(0.2738/0.004041)

=$389900×1.2738-917.142×67.756

= 496654.62-62141.87

FV = $434512.75

Therefore total payment made with interest over the life of the loan= balloon payment+ constant payments for five years= $434512.75+$55028.52

=

6 0
3 years ago
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