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3 years ago

What is the difference between -131 and -87 on a number line

Mathematics

2 answers:

Crank3 years ago

7 0

44 because the absolute values are 131 and 87 and to find difference you subtract.

disa [49]3 years ago

5 0

Correction it is -44 Sense they are negative

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2/5 of a number is what percentage of that number?

Contact [7]

Answer:

40%

Step-by-step explanation:

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3 years ago

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Pleaseeeee helppppp!!!

Delicious77 [7]

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3 years ago

Evaluate. -|-7 + 3| <br> 4<br> -4<br> -10

agasfer [191]

Your answer is 4

You have to use the distribute property and distribute the - to the -7 and the 3

The -7 will become and the 3 will become -3

Then you add those together and when you add a negative to a positive you basically subtract

So 7+-3 is 4

A is your answer

3 0

4 years ago

50 POINTS!!!!!

Makovka662 [10]

We can adjust the data by adding 4 to everything before we calculate the statistics. Or we can calculate the statistics on the given data and just add 4 to everything at the end. We'll get the same answer either way.

Let's sort the seven data points: 5 5 5 7 7 9 10

Those add up to 48 so the mean is 48/7 = 6.9

The one in the middle is 7 so the median = 7

The mode is the most common one, mode = 5

The range is the difference between max and min, so range = 10 - 5 = 5

In the second week we add four to everything. Since that adds four to the min and max, the range doesn't change.

Answer: mean=10.9, median=11, mode=9, range=5

7 0

4 years ago

Hi! I need help with the attached question in calc. Thank you:)

Elena L [17]

Answer:

3π square units.

Step-by-step explanation:

We can use the disk method.

Since we are revolving around AB, we have a vertical axis of revolution.

So, our representative rectangle will be horizontal.

R₁ is bounded by y = 9x.

So, x = y/9.

Our radius since our axis is AB will be 1 - x or 1 - y/9.

And we are integrating from y = 0 to y = 9.

By the disk method (for a vertical axis of revolution):

$\displaystyle V=\pi \int_a^b [R(y)]^2\, dy$

So:

$\displaystyle V=\pi\int_0^9\Big(1-\frac{y}{9}\Big)^2\, dy$

Simplify:

$\displaystyle V=\pi\int_0^9(1-\frac{2y}{9}+\frac{y^2}{81})\, dy$

Integrate:

$\displaystyle V=\pi\Big[y-\frac{1}{9}y^2+\frac{1}{243}y^3\Big|_0^9\Big]$

Evaluate (I ignored the 0):

$\displaystyle V=\pi[9-\frac{1}{9}(9)^2+\frac{1}{243}(9^3)]=3\pi$

The volume of the solid is 3π square units.

Note:

You can do this without calculus. Notice that R₁ revolved around AB is simply a right cone with radius 1 and height 9. Then by the volume for a cone formula:

$\displaystyle V=\frac{1}{3}\pi(1)^2(9)=3\pi$

We acquire the exact same answer.

8 0

3 years ago