Answer: 30
Step-by-step explanation:
Given: The number of entrance to the haunted house= 6
Also we can not exist from the same way of entrance.
Then the number of choices of exit will be 5.
Now, the number of different ways you can enter and exit the house =
Hence, the number of different ways you can enter and exit the house = 30
(5x+1) If X=3 then 5(3)+1=16
(2×2y) if Y=2 then 2×(2)2=8
16÷8=2
Answer:
276 Guests
Calculation to determine how many guest were at the wedding
Guests that choose beef =1/3
Guests that choose chicken= 5/12
Guests that choose vegetarian=69
Now let calculate the how many guest were at the wedding
Let x represent the numbers of guest that were present at the wedding
Hence,
x/3 + 5x/12 + 69 = x
9x/12 + 69 = x
12x/12 - 9x/12 = 69
3x/12 = 69
x/4 = 69
x=69*4
x = 276 guests
Therefore the numbers of guests that were at the wedding is 276
The GCF for 84 and 90 is 6.
The factors of 84 are: 1, 2, 3, 4, <u>6</u>, 7, 12, 14, 21, 28, 42, 84
The factors of 90 are: 1, 2, 3, 5, <u>6</u>, 9, 10, 15, 18, 30, 45, 90
Then the greatest common factor is 6.