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Yanka [14]
3 years ago
14

There 6 entrances to the haunted house. If you do not exit the same way you entered, how many different ways can you enter and e

xit the house?
Mathematics
2 answers:
zlopas [31]3 years ago
5 0
I believe 30, because there are six ways in and five ways out, five because you can't go back through the same entrance. So six times five is thirty.
7nadin3 [17]3 years ago
4 0

Answer: 30

Step-by-step explanation:

Given: The number of entrance to the haunted house= 6

Also we can not exist from the same way of entrance.

Then the number of choices of exit will be 5.

Now, the number of different ways you can enter and exit the house = 6\times5=30

Hence, the number of different ways you can enter and exit the house = 30

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(5x+1) If X=3 then 5(3)+1=16

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6 0
4 years ago
Jay organised a large wedding and 1/3 of them chose beef 5/12 of them chose Chicken and 69 of them chose vegetarian so how many
DerKrebs [107]

Answer:

276 Guests

Step-by-step explanation:

Calculation to determine how many guest were at the wedding

Guests that choose beef =1/3

Guests that choose chicken= 5/12

Guests that choose vegetarian=69

Now let calculate the how many guest were at the wedding

Let x represent the numbers of guest that were present at the wedding

Hence,

x/3 + 5x/12 + 69 = x

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7 0
3 years ago
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What's 99 divided by 9,801
Akimi4 [234]
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99 divided by 9801 = 0.01
7 0
3 years ago
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What is the GCF for 84 and 90
vivado [14]

Answer:

The GCF for 84 and 90 is 6.

Step-by-step explanation:

The factors of 84 are: 1, 2, 3, 4, <u>6</u>, 7, 12, 14, 21, 28, 42, 84

The factors of 90 are: 1, 2, 3, 5, <u>6</u>, 9, 10, 15, 18, 30, 45, 90

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3 years ago
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