There 6 entrances to the haunted house. If you do not exit the same way you entered, how many different ways can you enter and e
2 answers:
Answer: 30
Step-by-step explanation:
Given: The number of entrance to the haunted house= 6
Also we can not exist from the same way of entrance.
Then the number of choices of exit will be 5.
Now, the number of different ways you can enter and exit the house =
Hence, the number of different ways you can enter and exit the house = 30
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sin(x+y)=sin(x)cos(y)-cos(x)sin(y)
also, remember pythagorean rule,
given that sin(Θ)=4/5 and cos(x)=-5/13
find sin(x) and cos(Θ)
sin(x)
cos(x)=-5/13
using pythagorean identity
(sin(x))^2+(-5/13)^2=1
sin(x)=+/- 12/13
in the 2nd quadrant, sin is positve so sin(x)=12/13
cos(Θ)
sin(Θ)=4/5
using pythagrean identity
(4/5)^2+(cos(Θ))^2=1
cos(Θ)=+/-3/5
in 1st quadrant, cos is positive
cos(Θ)=3/5
so sin(Θ+x)=sin(Θ)cos(x)+cos(Θ)sin(x)
sin(Θ+x)=(4/5)(-5/13)+(3/5)(12/13)
sin(Θ+x)=16/65
answer is 1st option