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Yanka [14]
3 years ago
14

There 6 entrances to the haunted house. If you do not exit the same way you entered, how many different ways can you enter and e

xit the house?
Mathematics
2 answers:
zlopas [31]3 years ago
5 0
I believe 30, because there are six ways in and five ways out, five because you can't go back through the same entrance. So six times five is thirty.
7nadin3 [17]3 years ago
4 0

Answer: 30

Step-by-step explanation:

Given: The number of entrance to the haunted house= 6

Also we can not exist from the same way of entrance.

Then the number of choices of exit will be 5.

Now, the number of different ways you can enter and exit the house = 6\times5=30

Hence, the number of different ways you can enter and exit the house = 30

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Solve the equation 6/5y-10=-4<br> X=
defon

6/5y-10=-4

move -10 to the other side

sign changes from -10 to 10

6/5y-10+10= -4+10

6/5y= 6

Mutiply by 5/6 for both sides

6/5(5/6)y=6(5/6)

Cross out 6/5 and 5/6 , divide by 5 and 6 then becomes y

Cross out 5 and 6 on the right side

x= 5

Answer : x= 5

3 0
3 years ago
R
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i have no idea what question you need answered

7 0
3 years ago
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Please explain with your answer
Gala2k [10]

Answer:

D

Step-by-step explanation:

Note there is a common difference d between consecutive terms in the sequence, that is

d = 2 - 5 = - 1 - 2 = - 4 - (- 1) = - 3

This indicates that the sequence is arithmetic with n th term

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 5 and d = - 3, thus

a_{40} = 5 - 3(39) = 5 - 117 = - 112 → D

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3 years ago
(c) Which is greater, 300 kelvins or 25 degrees Celsius? Show your work.
mixer [17]
I think 300 kelvins is greater 
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3 years ago
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What polynomial when divided by 2y^5 yields 4y^2-2y+9 as a quotient?
Sedbober [7]
w(x):2y^5=4y^2-2y+9\Rightarrow w(x)=2y^5(4y^2-2y+9)\\\\w(x)=2y^5\cdot4y^2-2y^5\cdot2y+2y^5\cdot9\\\\w(x)=8y^7-4y^6+18y^5
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