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2 years ago

2(x+3)^2=49 A. 1.95 and 7.95 B. -1.95 and -7.95 C.1.95 and -7.95 D.4 and -10

Mathematics

1 answer:

Deffense [45]2 years ago

4 0

$2(x + 3)2 = 49$
A 1.95 and 7.95

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Need help with a simple problem 2^x=3^x+1

KiRa [710]

For $x\ \textgreater \ 0$ , $2^x\ \textless \ 3^x$ , all the more $2^x\ \textless \ 3^x+1$ , therefore no solution.

For $x=0$ , we have $2^0=3^0+1 \Rightarrow 1=1+1 \Rightarrow 1=2$ . Obviously that' false.

For $x\ \textless \ 0$ both $2^x$ and $3^x$ , where $2^x\ \textgreater \ 3^x$ , belong to the range $(0,1)$ , then $3^x+1$ belong to the range $(1,2)$ .
Those ranges don't have a common part, therefore, again, no solution.

So, the equation $2^x=3^x+1$ doesn't have a solution.

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3 years ago

In a test, John was able to answer 15 correct out of 40 questions. Beth was able to answer 24 questions correctly out of 50. Mic

Helen [10]

Answer:

that is wrong beth has a better score

Step-by-step explanation:

14 out of 40 is 37.5%

and 24 out of 50 is 48%

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2 years ago

find three consecutive negative integers such that six times the largest is equal to the twice sum of the two smaller integers.

Oksana_A [137]

Answer:

The consecutive negative integers are -3, -4 and -5.

Step-by-step explanation:

Let the three consecutive negative integers be k, (k-1) and (k -2)

Now, according to the question:

6(Largest Integer) = 2( Sum of smaller two Integers)

or, 6 (k) = 2( (k-1) + (k-2))

⇒ 6k = 2(2k -3)

or, 6k = 4k - 6

or, 6k - 4k = -6

or, 2k = -6 ⇒ k = -3

Hence, the largest negative integer = -3

The next two consecutive negative integer are (k-1) and (k-2) = (-3-1) and (-3-2)

= -4 and -5

Hence, the consecutive negative integers are -3, -4 and -5.

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2 years ago

What number is not a composite number 2,9,15,21?

Citrus2011 [14]

2 is not a composite number

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3 years ago

How do you write 3.684 × 103 in standard form?

lys-0071 [83]

The answer is 379.452

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2 years ago