Question

Factoring , a² +4a - 5

Answer 1

the factors of the term $a^2+4a-5$ are $(a-1)(a+5)$

Step-by-step explanation:

We need to find factors of the term: $a^2+4a-5$

For finding factors:

We need to break the middle term such that their product is equal to product of first and last term and their sum is equal to middle term

Breaking the middle term and finding factors:

$a^2+4a-5$

$=a^2+5a-a-5$

$=a(a+5)-1(a+5)$

$=(a-1)(a+5)$

So, the factors of the term $a^2+4a-5$ are $(a-1)(a+5)$

Keywords: Finding factors

Learn more about finding factors at:

• brainly.com/question/9045597
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• brainly.com/question/13168205

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