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Alik [6]
3 years ago
14

Can you tell me which statements go in "agree" and "disagree"?

Mathematics
1 answer:
stepan [7]3 years ago
4 0

Answer:

Step-by-step explanation:

wefasv

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If two numbers round to the same number, does that mean the numbers are equal?
Eduardwww [97]
If two numbers round to the same number it doesnt always mean they are equal, for example: 11 and 9 both round to ten but they are not the same number
3 0
3 years ago
Read 2 more answers
Match each series with the equivalent series written in sigma notation
PIT_PIT [208]

Answer:

3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n

4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n

2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n

3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n

Step-by-step explanation:

Given

See attachment for complete question

Required

Match equivalent expressions

Solving (a):

3 + 12 + 48 + 192 + 768

The expression can be written as:

3 \to 3*4^{0 --- 0

12 \to 3 * 4^{1 ---- 1

48 \to 3 * 4^{2 --- 2

192 \to 3 * 4^{3 ---- 3

768 \to 3 * 4^{4 ---- 4

For the nth term, the expression is:

Term = 3 * 4^{n ---- n

So, the summation is:

3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n

Solving (b):

4 + 32 + 256 + 2048 + 16384

The expression can be written as:

4 \to 4 * 8^0 --- 0

32 \to 4 * 8^1 ---- 1

256 \to 4 * 8^2 --- 2

2048 \to 4 * 8^3 ---- 3

16384 \to 4 * 8^4 ---- 4

For the nth term, the expression is:

Term \to 4 * 8^n ---- n

So, the summation is:

4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n

Solving (c):

2 + 6 + 18 + 54 + 162

The expression can be written as:

2 \to 2 * 3^0 --- 0

6 \to 2 * 3^1 ---- 1

18 \to 2 * 3^2 --- 2

54 \to 2 * 3^3 ---- 3

162 \to 2 * 3^4 ---- 4

For the nth term, the expression is:

Term \to 2 * 3^n ---- n

So, the summation is:

2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n

Solving (d):

3 + 15 + 75 + 375 + 1875

The expression can be written as:

3 \to 3 * 5^0 --- 0

15 \to 3 * 5^1 ---- 1

75 \to 3 * 5^2 --- 2

375 \to 3 * 5^3 ---- 3

1875 \to 3 * 5^4 ---- 4

For the nth term, the expression is:

Term \to 3 * 5^n ---- n

So, the summation is:

3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n

5 0
3 years ago
ANSWER PLEASE
SSSSS [86.1K]

Answer:

5/8

Step-by-step explanation:

7 0
3 years ago
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***PLZ HELP ME***
erica [24]
A is inbetween 2 and 4
B is inbetween 3 and 4
 C is inbetween 4 and 5
D is inbetween 5 and 6

So the correct answer would be A B and C
8 0
3 years ago
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From data gathered in the period 2008−2012, the yearly value of U.S. exports can be modeled by the function E(x) = −228x3 + 2,25
vredina [299]

Answer:

The total value the U.S. imported and exported is 19364 billion dollars

Step-by-step explanation:

* Lets explain how to solve the problem

- The yearly value of U.S. exports can be modeled by the function

 E(x) = −228 x³ + 2,252.8 x² − 6,098.5 x + 11,425.8

# x is the number of years after 2008

# E(x) is the value of exports in billions of dollars

- The yearly value of U.S. imports can be modeled by the function

 I(x) = −400.4 x³ + 3,954.4 x² − 11,128.8 x + 17,749.6

# x is the number of years after 2008

# I(x) is the value of imports in billions of dollars

* We need to calculate the total value the U.S. imported and

 exported in 2012

∵ x is the number of years after 2008

∴ At 2012 x = 4 years

- Lets calculate the value of the exports in 2012

∴ E(x) = -228(4)³ + 2,252.8(4)² - 6,098.5(4) + 11,425.8

∴ E(x) = 8484.6 billion dollars

- Lets calculate the value of the imports in 2012

∴ I(x) = -400.4(4)³ + 3,954.4(4)² - 11,128.8(4) + 17,749.6

∴ I(x) = 10879.2 billion dollar

∵ The total value the U.S. imported and exported = E(x) + (I(x)

∴ The total value = 8484.6 + 10879.2 = 19363.8

∴ The total value = 19364 billion dollars

* The total value the U.S. imported and exported is 19364 billion dollars

7 0
3 years ago
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