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Alik [6]
3 years ago
14

Can you tell me which statements go in "agree" and "disagree"?

Mathematics
1 answer:
stepan [7]3 years ago
4 0

Answer:

Step-by-step explanation:

wefasv

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Two Pounds of grapes cost six dollars complete the table showing the price of different amounts of grapes at this rate.
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do lsibras a  6 dolares cadanax  u

Step-by-step explanation:

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What is5400300 in standard form
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Five Millon four thousand and three hundred
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What is the domain of y=4sin(x)?
stealth61 [152]

Answer:

( − ∞ , ∞ )  { x | x ∈ R }

Step-by-step explanation:

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

4 0
3 years ago
Heather is 5 feet 7 inches tall. There are
lisabon 2012 [21]
Heather is about 167.5 cm

5’7” is equal to 67 inches
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3 years ago
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An automobile manufacturer would like to know what proportion of its customers are not satisfied by the service provided by the
zheka24 [161]

Answer:

The sample size needed if the margin of error of the confidence interval is to be about 0.04 is 18.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Past studies suggest this proportion will be about 0.15

This means that p = 0.15

Find the sample size needed if the margin of error of the confidence interval is to be about 0.04

This is n when M = 0.04. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.15*0.85}{n}}

0.04\sqrt{n} = 1.96\sqrt{0.15*0.85}

\sqrt{n} = \frac{1.96\sqrt{0.15*0.85}}{0.04}

(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.15*0.85}}{0.04})^{2}

n = 17.5

Rounding up

The sample size needed if the margin of error of the confidence interval is to be about 0.04 is 18.

8 0
2 years ago
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