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Over [174]
4 years ago
12

Thomas's coach tells him to run 600 yards after practice. How many feet should Thomas Run ?

Mathematics
1 answer:
BaLLatris [955]4 years ago
8 0
1 yard is equal to 3 feet, so multiply 600*3. Which =1800 feet
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marissa [1.9K]
It’s b
Z+23=41
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3 years ago
Find the arc length of the partial circle. <br>length is 1.<br>**See attached photo**<br>​
KatRina [158]

Arc length of the quarter circle is 1.57 units.

Solution:

Radius of the quarter circle = 1

Center angle (θ) = 90°

To find the arc length of the quarter circle:

$\text{Arc length}=2 \pi r\left(\frac{\theta}{360^\circ}\right)

                 $=2 \times 3.14  \times 1\left(\frac{90^\circ}{360^\circ}\right)

                $=2 \times 3.14  \times 1\left(\frac{1}{4}\right)

Arc length = 1.57 units

Arc length of the quarter circle is 1.57 units.

5 0
3 years ago
PLEASE HELP ASAP
Vlad [161]

Answer:

  1 : 6 . . . . or 1/6

Step-by-step explanation:

We know 1 foot is 12 inches, so 5 feet is 5·12 = 60 inches. Zachary's scale factor is ...

  drawing size : actual size = 10 inches : 60 inches = 1 : 6

This can also be written as the fraction 1/6.

5 0
3 years ago
I need help please who ever do this one question there are a real one :(
Phoenix [80]

Answer:

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Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
At 6:00 PM, a flagpole that is 35 feet tall casts a shadow that is 50 feet long. At the same time, how long will a person's shad
sertanlavr [38]

<u>Answer:</u>

The length of the person’s shadow is 5.7ft

<u>Explanation:</u>

Length of the flagpole =a= 35ft

Length of the shadow of the flagpole= b=50ft

Length of the person=c= 4ft

Suppose the length of the person’s shadow is=d

According to the  rules of trigonometry

\frac{\text { Length of the flagpole }}{\text { Length of the shadow of the flagpole }}=\frac{\text { Length of the person }}{\text { Length of the person's shadow }}

\frac{a}{b}=\frac{c}{d}

\frac{35}{50}=\frac{4}{d}

35d=200

d=\frac{200}{35}

d=5.7ft  

Hence, The length of the person’s shadow is 5.7ft.

3 0
3 years ago
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