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Tema [17]
3 years ago
11

A plane traveled 1248 miles to Ft. Worth and back. The trip there was with the wind. It took 12

Mathematics
1 answer:
Artemon [7]3 years ago
6 0

speed of the  plane in still air is 76 m/s and speed of the wind is 28 m/s .

<u>Step-by-step explanation:</u>

Here we have , A plane traveled 1248 miles to Ft. Worth and back. The trip there was with the wind. It took 12  hours. The trip back was into the wind. The trip back took 24 hours. We need to find What is the speed of the  plane in still air? What is the speed of the wind? Let's find out :

<u>For Going trip :</u>

Let speed of plane be u , and wind be v so : Speed = ( Distance ) / ( time )

⇒ u+v = \frac{1248}{12}

⇒ u+v = 104   ...........(1)

<u>For Returning Trip :</u>

⇒ u-v = \frac{1248}{24}

⇒ u-v = 52   ...........(2)

Adding both equations we get :

⇒ (u+v)+(u-v)=104+52

⇒ 2u=156

⇒ u= 76m/s

Putting this value in equation (1) we get :

⇒ 76+v = 104

⇒ v=28m/s

Therefore , speed of the  plane in still air is 76 m/s and speed of the wind is 28 m/s .

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The taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Given a function f(x)=9/x,a=-4.

We are required to find the taylor series for the function f(x)=8/x centered at the given value of a and a=-4.

The taylor series of a function f(x)=f(a)+f^{1}(a)(x-a)/1!+ f^{11}(a)(x-a)^{2} /2! +f^{111}(a)(x-a)a^{3}/3!+..........

Where the terms in f prime f^{1}(a) represent the derivatives of x valued at a.

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=-1/2

The series of f(x) is as under:

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=8/(-4)-8/(-4)^{2} (-4)(x+4)/1!+  24/(-4)^{3} (-4)(x+4)^{2}/2!.............

=-2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Hence the taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Learn more about taylor series at brainly.com/question/23334489

#SPJ4

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