Question

Which value must be added to the expression x2 + 16x to make it a perfect-square trinomial?

Answer 1

Before getting to the actual answer, one must be aware of the way the answer is found. The one and only thing that needs to be done in this case is finding the half of 16 and then squaring it. This obviously gives the result as 64. he correct option among all the options that are given in the question is the third option or option "C". 

Answer 2

Answer:

$\text{64 must be added to the expression }x^2 + 16x\text{ to make it a perfect-square trinomial}$

Step-by-step explanation:

Given the expression

$x^2+16x$

we have to tell which value must be added to the above expression to make it a perfect-square trinomial.

Expression: $x^2+16x$

By completing the square method,

The square of half of the coefficient of x must be added , we get

$x^2+16x+64$

$x^2+8x+8x+64$

$x(x+8)+8(x+8)$

$(x+8)^2$

which is a perfect square.

$\text{Hence, 64 must be added to the expression }x^2 + 16x\text{ to make it a perfect-square trinomial}$