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2 years ago

4x/5-12=20 PLEASE I REALLY NEED HELP

1 answer:

8 0

$\dfrac{4x}{5}-12=20\ \ \ \ |add\ 12\ to\ both\ sides\\\\\dfrac{4x}{5}=32\ \ \ \ |multiply\ both\ sides\ by\ 5\\\\4x=160\ \ \ \ |divide\ both\ sides\ by\ 4\\\\\boxed{x=40}$

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A train traveled at a constant rate of f feet per second. how many feet did it travel in x minutes? (a) 60f x (b) fx 60 (c) x 60

sdas [7]

Distance travelled by train in x minutes is equal to 60fx feet as per given constant rate of f feet per second.

As given in the question,

Train travelled at a constant rate f feet per second

Let d be the distance travelled by train in x minutes

1 second =f feet

60 seconds = (60f) feet

1 minute = (60f) feet

x minutes = (60fx)feet

Therefore ,distance travelled by train in x minutes is equal to 60fx feet

as per given constant rate of f feet per second.

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1 year ago

A rectangle prism has three dimension

Airida [17]

Answer:

yes but what is your question?

Step-by-step explanation:

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2 years ago

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Jane uses 11 cups of flour for 5 cakes. how much would she need for 60 cakes?

SVETLANKA909090 [29]

Answer:

132

Step-by-step explanation:

11 / 5 = 2.2

2.2 x 60 = 132

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2 years ago

Use the zero product property to find the solutions to the equation 2x2 + x - 1 = 2

Firdavs [7]

Answer:

Step-by-step explanation:

Given

2x² + x - 1 = 2 ( subtract 2 from both sides )

2x² + x - 3 = 0

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 2 × - 3 = - 6 and sum = + 1

The factors are - 2 and + 3

Use these factors to split the x- term

2x² - 2x + 3x - 3 = 0 ( factor the first/second and third/fourth terms )

2x(x - 1) + 3(x - 1) = 0 ← factor out (x - 1) from each term

(x - 1)(2x + 3) = 0

Equate each factor to zero and solve for x

x - 1 = 0 ⇒ x = 1

2x + 3 = 0 ⇒ 2x = - 3 ⇒ x = - $\frac{3}{2}$

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3 years ago

To rent a jet ski at Hayden’s cost is $25 plus $3 per hour. At Austin’s, it costs $5 plus $8 per hour. At how many hours will th

Katen [24]

<u>At Hayden's:</u>

$(25+3)= \ 28+3 \ (2nd \ hour)=31+3 \ (3rd \ hour)=34+3 . . . \swarrow\swarrow \\ \ \Longrightarrow \Longrightarrow \Longrightarrow \Longrightarrow \Longrightarrow \Longrightarrow \Longrightarrow \Longrightarrow \Longrightarrow \Longrightarrow \Longrightarrow \boxed{34+3=37}= \ (4rth \ Hour)$

<u>At Austins:</u>

$(5+8)= \ (first \ hour) = 13+8= \ 21 = (2nd \ hour) \ 21+8=29= \ \swarrow \\ \longrightarrow \ 29=(3rd \ hour)=\boxed{ 29+8= (37)= \ ((Forth \ hour))}$

As we can see in both results, it would take them (4 hours) for the prices to be equaled.

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3 years ago