Answer:
lateral area = 2320 m²
Step-by-step explanation:
The question wants us to calculate the lateral area of a square base pyramid. The square base pyramid has a side of 40 meters.The height is 21 meters.
Half of the square base is 40/2 = 20 meters . With the height it forms a right angle triangle. The hypotenuse side is the slant height of the pyramid.
Using Pythagoras's theorem
c² = a² + b²
c² = 20² + 21²
c² = 400 + 441
c² = 841
square root both sides
c = √841
c = 29 meters
The slant height of the pyramid is 29 meters.
The pyramid has four sided triangle. The lateral area is 4 multiply by the area of one triangle.
area of triangle = 1/2 × base × height
base = 40 meters
height = 29 meters
area = 1/2 × 40 × 29
area = 580
area of one triangle = 580 m²
Lateral area = 4(580)
lateral area = 2320 m²
Answer:
x=11/5, or x=2.2.
Step-by-step explanation:
9-3(x+4)=2(x-3)-8
9-3x-12=2x-6-8
9-12-3x=2x-14
-3-3x=2x-14
-3-3x-2x=-14
-3-5x=-14
5x=-3-(-14)
5x=-3+14
5x=11
x=11/5
x=2.2
Answer:
8 years approximately
The problem (I'm assuming is):
Solve 
.
I put a t in the problem where I suspected it in went.
Step-by-step explanation:
Divide both sides by 100:
Rewrite in logarithm form.
Divide both sides by 0.05:
Put left hand side into calculator:
So about 8 years if I wrote down the equation correctly.
The answer would be D because you are subtracting a positive 17 from a positive 88
Upon slight rearranging:
5xy-15y-40x+120, now factor 1st and 2nd pair of terms
5y(x-3)-40(x-3) which is equal to:
(5y-40)(x-3) if we factor the first parenthetical term as well
5(y-8)(x-3)
So (y-8) is a factor
