What is the correct Lewis structure for Group 5A element, Arsenic? A B C D
2 answers:
Answer : The correct representation of Lewis-dot structure for 5A element, Arsenic is shown below.
Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.
The number of valence electrons shown by 'dot'.
The given molecule is, Arsenic
The atomic number of arsenic = 33
As we know that the number of electrons is equal to the number of atomic number.
So, the number of electrons = 33
The electronic configuration of arsenic is,
The number of valence electrons present in arsenic = 5
The Lewis-dot structure of arsenic is shown below.
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Answer : The correct option is C.
Explanation :
Enthalpy of reaction : It is defined as the changes in heat energy takes place when reactants go to products. It is denotes as .
= Energy of product - Energy of reactant
is positive when heat is absorbed and the reaction is endothermic.
is negative when heat is released and the reaction is exothermic.
In the given potential energy diagram, the energy of product at higher level and energy of reactant at lower level. The for this reaction will be positive.
So, the enthalpy of reaction is defined as the difference of the energy of the reactants and the energy of the products.
Answer:see attached image
Explanation:
In organic chemistry, a product may be kinetically or thermodynamically favoured. A kinetically favours product forms faster, it may not necessarily be the more stable product. The thermodynamically favoured product forms at a slower rate but is more stable. Often times, the kinetically favoured product rearranges itself to form the thermodynamically favoured product at equilibrium. The endo product of the Diels Alder reaction mentioned in the question is first formed (kinetically favoured) but rearranges to form the exo product (thermodynamically favoured) at equilibrium. This is clear shown in the reaction mechanism attached below.
Answer: a) is the limiting reagent
b) 3.59 g
c) 11.6g
Explanation:
To calculate the moles :
According to stoichiometry :
a) 9 moles of require= 4 moles of
Thus 0.15 moles of will require=
of
Thus is the limiting reagent as it limits the formation of product and
is the excess reagent.
b) As 9 moles of give = 8 moles of
Thus 0.15 moles of give =
of
Mass of
c) As 9 moles of give = 3 moles of
Thus 0.15 moles of give =
of
Mass of