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faust18 [17]
3 years ago
8

Metals are really good thermal conductors for which of the following reasons? Select all that apply. Metals are really good ther

mal conductors for which of the following reasons?
Select all that apply.

Metals can absorb more heat flow than other elements before damage occurs.
Particles of metallic structure begin to vibrate faster as they absorb energy.
Metals have a larger number of freely moving electrons.
Metals have high densities.
Metals have high melting points.
Chemistry
2 answers:
prisoha [69]3 years ago
8 0

Explanation:

Metals are the substances that hold greater number of free electrons. Also, metals as utensil, cookware etc have molecules closer to each other.

Therefore, heat transfer becomes fast from one molecule to another. As a result, due to increase in degree of compactness, that is, density makes metals good conductor of heat.

Thus, we can conclude that metals are really good thermal conductors for the following reasons:

  • Particles of metallic structure begin to vibrate faster as they absorb energy.
  • Metals have a larger number of freely moving electrons.
  • Metals have high densities.
Natasha_Volkova [10]3 years ago
7 0

B. Particles of metallic structure begin to vibrate faster as they absorb.

C. Metals have a larger number of freely moving electrons.

D. Metals have high densities.

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At 2000°C, the equilibrium constant for the reaction below is Kc = 4.10 ´ 10–4 . If 0.600 moles of NO is placed in a 1.0-L react
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Answer:

At equilibrium, the concentration of N_{2 (g)} is going to be 0.30M

Explanation:

We first need the reaction.

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N_{2 (g)} + O_{2 (g)} ⇄ 2NO_{(g)}

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By the ICE (initial, change, equilibrium) analysis:

I: [N_{2 (g)}]=0   ;     [O_{2 (g)} ]= 0    ; [NO_{(g)}]=0.60M

C: [N_{2 (g)}]=+x   ;     [O_{2 (g)} ]= +x    ; [NO_{(g)}]=-2x

E: [N_{2 (g)}]=0+x   ;     [O_{2 (g)} ]= 0+x   ; [NO_{(g)}]=0.60-2x

Now we can use the constant information:

K_{c}=\frac{[products]^{stoichiometric coefficient} }{[reactants]^{stoichiometric coefficient} }

4.10* 10^{-4} =\frac{(0.60-2x)^{2}}{(x)*(x)}

4.10* 10^{-4}= \frac{(0.60-2x)^{2}}{x^{2} }

4.10* 10^{-4} * x^{2}= (0.60-2x)^{2}}

\sqrt{4.10* 10^{-4} * x^{2}}= \sqrt{(0.60-2x)^{2}}}

0.0202 x =0.60 - 2x

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x=\frac{0.60}{2.0202}= 0.30

At equilibrium, the concentration of N_{2 (g)} is going to be 0.30M

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Answer:

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