To start this question, we should know what is the atomic number of cobalt. The atomic number (the number of protons) of Cobalt is Z =27.
Now, we know that a Cobalt 60 isotope means an isotope of Cobalt whose Atomic Mass is 60.
Thus, in a Cobalt 60 isotope, the number of neutrons in the nucleus are

From the question we know that the given nuclear mass is 59.933820 u.
Now, the mass defect of Cobalt 60 can be easily calculated by adding the masses of the protons and the neutrons as per our calculations and subtracting the given nuclear mass from it.
Thus,
Mass Defect = (Number of Protons Mass of Proton given in the question) + (Number of Neutrons Mass of Neutron given in the question)-59.933820 u

Thus, the required Mass Defect is 0.5634u.
In eV, the Mass Defect is 
Answer:
its 2
Step-by-step explanation:
so 6x2 is 12 and 5x2 is 10
u have to find the gcf of 12 and 10 which is 2 :)
Answer:
C. (2, 1)
Step-by-step explanation:
-3y = x-5
x+ 5y = 7
Subtract x from both sides in the first equation. Write the second equation below it.
-x - 3y = -5
x + 5y = 7
Add the two equations above.
2y = 2
Divide both sides by 2.
y = 1
Substitute y with 1 in the second original equation and solve for x.
x + 5(1) = 7
x + 5 = 7
Subtract 5 from both sides.
x = 2
Answer: C. (2, 1)
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