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4 years ago

F(x)= 2x^2-3x-9 G(x)= 4x^2-9 find (f/g) (x)

Mathematics

1 answer:

Liono4ka [1.6K]4 years ago

8 0

Answer:

....

Step-by-step explanation:

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The air temperature in the North Pole in the morning was 3 degrees Celsius. By 10:00 am the temperature dropped 12 degrees. By n

WINSTONCH [101]

Answer: -11 degrees Celsius

Step-by-step explanation:

First you subtract 3-12 leaving -9 then you add positive 5 to -9 giving you -4 then add 9 to equal 5 and lastly 5- 16 to get -11.

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3 years ago

A card is drawn from a standard deck of 52 cards. What is the theoretical probability as a decimal of drawing the number 8? Roun

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The answer would be 0.15 because in a deck there are only 4 cards of 8 (diamonds, hearts, clovers, and spades). Since there are 52 cards, you would divide 8 by 52 to get 0.153846, but since it says to round to the nearest hundredths, the answer would be 0.15.

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3 years ago

Using the Distributive Property, find the product of the expression 7(22) and then simplify.

Artyom0805 [142]

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3 years ago

which equation in point-slope form contains the point (-3, 5) and has slope -1 ANSWERS y + 3 = -1(x-5) y-3= -1(x+5) y+5=-1(-3) y

castortr0y [4]

Answer:

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

m - slope

We have m = -1 and the point (-3, 5). Substitute:

$y-5=-1(x-(-3))\\\\y-5=-(x+3)$

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3 years ago

I need help w/ this!! thank you

Fittoniya [83]

<h3>Answer:</h3>

$\boxed{\pink{\sf \leadsto Yes \ there \ is \ a \ solution \ of \ the \ given \ inequality .}}$

<h3>Step-by-step explanation:</h3>

A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.

The inequality given to us is :-

$\bf\implies |2y + 3 | - 1 \leq 0 \\\\\bf\implies |2y+3|\leq 1 \\\\\bf\implies (|2y+3|)^2 \leq 1^2 \\\\\bf\implies (2y+3)^2 \leq 1 \\\\\bf\implies (2y)^2+3^2+2(2y)(3) \leq 1 \\\\\bf\implies 4y^2+9+12y - 1 \leq 0 \\\\\bf\implies 4y^2+12y+8 \leq 0 \\\\\bf\implies 4( y^2 + 3y + 2 ) \leq 0 \\\\\bf\implies y^2+3y +2 \leq 0 \:\:\bigg\lgroup \purple{\bf Standard \ form \ of \ inequality }\bigg\rgroup \\\\\bf\implies y^2y+2y+y+2 \leq 0 \\\\\bf\implies y(y+2)+1(y+2)\leq 0 \\\\\bf\implies ( y+2)(y+1)\leq 0 \\\\\bf\implies \boxed{\red{\bf y \leq (-2) , (-1) }}$

Let's plot a graph to see its interval . Graph attached in attachment .

Now we can see that the Interval notation of would be ,

$\boxed{\boxed{\orange \tt \purple{\leadsto}y \in [-2,-1] }}$

<h3>Hence the standard form of inequality is y²+3y +2 ≤ 0 and the Solution set of the inequality is [ -2 , -1 ] .</h3>

4 0

3 years ago