Question

Two unique letters are chosen at random from the alphabet.

Answer 1

A - choosing letter A first

$|\Omega|=P(26,2)=\dfrac{26!}{24!}=25\cdot26\\ |A|=1\cdot25=25\\\\ P(A)=\dfrac{25}{25\cdot26}=\dfrac{1}{26}\approx0.0385$

Answer 2

Answer:

A 0.0385

Step-by-step explanation:

There are in total 26 letters in English alphabet

Two unique letters are chosen at random.

I letter can be taken from any one of the 26 hence

probability for I letter to be a out of 26 letters = 1/26

We can convert this into decimal as

Probability  that the first letter chosen is A =0.0385

Option A is right answer.