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Verizon [17]
4 years ago
15

Do you have options or are you just supposed to simplify the ratio?

Mathematics
1 answer:
asambeis [7]4 years ago
8 0
Which ratio is equivalent to:
8 : 32
To simplify the ratio we have to find the greatest common factor ( GCF ) for the number on each side. Than we have to divide both by GCF.
 GCF ( 8, 32 ) = 8;  8 : 8 = 1;   32 : 8 = 4
Answer: D ) 1 : 4 
You might be interested in
Points D and E are midpoints of the sides of triangle ABC. The perimeter of the triangle is 48 units. Triangle A B C is shown. P
Sholpan [36]

Answer:

2

Step-by-step explanation:

From the diagram attached :

AB = AD + BD = 3t + 3t = 6t

BC = BE + EC = 4t + 4t = 8t

AC = 7t + 6

Perimeter of the triangle = 48

Perimeter of a triangle (P) :

P = AB + BC + AC

48 = 6t + 8t + 7t + 6

48 - 6 = 6t + 8t + 7t

42 = 21t

t = 42 / 21

t = 2

5 0
4 years ago
Read 2 more answers
...................answer
OleMash [197]

Answer:

140

Step-by-step explanation:

5x4x7=140

7 0
3 years ago
Read 2 more answers
Carmen has a sign with dimensions 5 ft × 7.5 ft. She wants to reduce it to make a postcard. Postcard sizes are 3.5 in. × 5 in.,
prisoha [69]

Answer:

The size of the post card she should use is 4 in. × 6 in.

Step-by-step explanation:

The parameters given are;

Dimensions of sign = 5 ft. × 7.5 ft

Hence, the ratio of the side sizes are;

5:7.5 which is the same as 2:3, therefore, to obtain the most accurate design of the sign on the post card, the size of the post card must be in direct proportion to the size of the sign which gives;

Side length ratio of post card = 2:3 = 4:6 = 4 in. × 6 in.

The size of the post card she should use is therefore = 4 in. × 6 in.

6 0
3 years ago
Find the perimeter of a regular hexagon with a side of 8 meters
dolphi86 [110]

Answer:

8 x 6 = 48

Step-by-step explanation:

Hexagon = 6 sides

8 x 6 = 48

4 0
4 years ago
Read 2 more answers
Solve the inequality of 5+2x<9
dlinn [17]
Hello,

Shall we begin?

5 + 2x < 9
2x < 9 - 5
2x < 4
x < 4/2
x< 2

<span>Answers:x < 2</span>
4 0
3 years ago
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