Question

What is the solution of √2x+4 -√x-2?

Answer 1

I hope this answer helped u

Answer 2

OK either the equation is $\sqrt{} 2x+4 - \sqrt{x} -2 =0$ or $\sqrt{} 2x+4 = \sqrt{x} -2$  Either way it ends up the same because if it is the first equation, I would move the $\sqrt{x} - 2$ to the other side of the equation.  It would become $\sqrt{x} + 2$.

For my example, I am going with $\sqrt{} 2x+4 = \sqrt{x} -2$ 
Square both sides
2x+4=$(x+2)^{2}$
Then use FOIL to solve the right side
2x+4=$x^{2} +2x+2x+4$
Then combine like terms
2x+4=$x^{2} +4x+4$
Set it equal to 0 and combine like terms
$0= x^{2} -2x$
0=x(x-2)
So x=0 and x=2
If it was the other was it would be x=-2

Hope that helps.