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Aleksandr [31]
3 years ago
10

A new car is purchased for 20300 dollars. The value of the car depreciates at 9.5% per year. What will the value of the car be,

to the nearest cent, after 11 years?
Mathematics
1 answer:
Iteru [2.4K]3 years ago
6 0
The starting value is 20,300, and the value is decreasing by 9.5% each year.

Because it decreases by 9.5% each year based on the previous amount, we use an exponential decay model.

A decrease by 9.5% corresponds to multiplying by 91.5% each year.

We write . We plug in 11 years for t.

A(t)=23000(0.915)^{t}\\\\A(11)=23000(0.915)^{11}\\\\A(11)=7671.18

$7,671.18
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If three points (5,1) , (1,-1) and (m,4) are collinear.Find m​
krek1111 [17]

Answer:

m = 11

Step-by-step explanation:

Since the points are collinear then the slope between points are equal.

Calculate the slope m using the slope formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (5, 1) and (x₂, y₂ ) = (1, - 1)

m = \frac{-1-1}{1-5} = \frac{-2}{-4} = \frac{1}{2}

Repeat with

(x₁, y₁ ) = (1, - 1) and (x₂, y₂ ) = (m, 4)

m = \frac{4+1}{m-1} = \frac{5}{m-1} = \frac{1}{2}

Cross- multiply

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m = 11

8 0
3 years ago
-5, 10 ,-20 ,40 value b
pychu [463]

Step-by-step explanation:

fold -2

40×(-2) = -80 ........

7 0
2 years ago
in 2009 a total of R36 000 was invested in two accounts. One account earned 7% annual interest and the other earned 9% .The tota
Akimi4 [234]

a = amount invested at 7%

b = amount invested at 9%

we know the amount invested was ₹36000, thus we know that whatever "a" and "b" are, a + b = 36000.  We can also say that

\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{7\% of a}}{\left( \cfrac{7}{100} \right)a}\implies 0.07a~\hfill \stackrel{\textit{9\% of b}}{\left( \cfrac{7}{100} \right)b}\implies 0.09b

since we know the interest earned from the invested was ₹2920, then we say that 0.07a + 0.09b = 2920.

\begin{cases} a + b = 36000\\\\ 0.07a+0.09b=2920 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{using the 1st equation}}{a + b = 36000\implies \underline{b = 36000-a}}~\hfill \stackrel{\textit{substituting on the 2nd equation}}{0.07a~~ + ~~0.09(\underline{36000-a})~~ = ~~2920} \\\\\\ 0.07a+3240-0.09a=2920\implies 3240-0.02a=2920\implies -0.02a=-320 \\\\\\ a=\cfrac{-320}{-0.02}\implies \boxed{a=16000}~\hfill \boxed{\stackrel{36000~~ - ~~16000}{20000=b}}

5 0
2 years ago
In basketball there are 3 ways to score: a free throw, worth 1 point, two
bazaltina [42]

Answer:

D

Step-by-step explanation:

I think it's D. Because you have that free shots give you 1 point so it is 1x or x , then you have two pointers which give you 2 points so it is 2y and you have three pointers which give you 3 points so it is 3z

4 0
3 years ago
16^3x+8^x+6<br><br>Could you please give me the steps as well for this problem? ​
BARSIC [14]

Answer:

x = 2

Step-by-step explanation:

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2^{12x} = 2^{3x+18}

Since the base number is 2, the exponents must equal each other.

So:

12x = 3x+18

9x = 18

x = 2

8 0
3 years ago
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