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lukranit [14]
4 years ago
8

What is the answer to this question?

Mathematics
1 answer:
Serjik [45]4 years ago
5 0

Answer:

For 2 hours of dog stinting the total cost will be the same for the two services.

Step-by-step explanation:

x to represent the number of hours of dog sitting

<u>Derrick's Dog Sitting </u>

Fixed charged rates  = $12

Sitting charges per hour  = $7

⇒Charges for x hours siting = x ( Charges per hour)

= x ( $7)  = 7x

⇒Total charges of Derrick's Dog Sitting  for x hours  = Fixed charge + Hourly Rate

= $7x + 12

<u> Darlene's Dog Sitting</u>

Fixed charged rates  = $16

Sitting charges per hour  = $5

⇒Charges for x hours siting = x ( Charges per hour)

= x ( $5)  = 5x

⇒Total charges of Darlene's Dog Sitting<u> </u>for x hours  = Fixed charge + Hourly Rate

= $5x + 16

Now, according to the question:

for x hours sitting, both company charges are same.

⇒ $7x + 12  =  $5x + 16

or, 7x - 5x = 16 - 12

or, 2x = 4

⇒ x =  2

Hence, for 2 hours of dog stinting the total cost will be the same for the two services.

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WARRIOR [948]

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For First Solution: y_1(t)=e^t

y_1(t)=e^t is the solution of equation y''-y=0.

For 2nd Solution:y_2(t)=cosht

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Step-by-step explanation:

For First Solution: y_1(t)=e^t

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

y_1(t)=e^t

First order derivative:

y'_1(t)=e^t

2nd order Derivative:

y''_1(t)=e^t

Put Them in equation y''-y=0

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Hence y_1(t)=e^t is the solution of equation y''-y=0.

For 2nd Solution:

y_2(t)=cosht

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

y_2(t)=cosht

First order derivative:

y'_2(t)=sinht

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y''_2(t)=cosht

Put Them in equation y''-y=0

cosht-cosht=0

0=0

Hence y_2(t)=cosht  is the solution of equation y''-y=0.

3 0
3 years ago
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