The area of the shaded region is [(169π/4)-60]m².
- The length of the rectangle is 12 m.
- The breadth of the rectangle is 5 m.
- The area of the rectangle = length * breadth.
- The area of the rectangle = 12 * 5
- The area of the rectangle = 60m²
- Let h be the diagonal of the rectangle.
- Using the Pythagorean theorem,
- h² = 12² + 5²
- h² = 144 + 25
- h² = 169
- h = √169
- h = 13
- The diagonal of the rectangle is also the diameter of the circle.
- Let r be the radius of the circle.
- 2r = 13
- r = 13/2m
- The area of the circle is πr².
- The area of the circle = π(13/2)²
- The area of the circle = (169π/4)m²
- The area of the shaded region equals the area of the circle minus the area of the rectangle.
- The area of the shaded region = [(169π/4) - 60]m²
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Answer: is 3a + b/5 if the equation is 1/5(15a+b) and is 75a+5b if it is 1*5(15a+b) I couldn’t tell if the 1 and 5 were a fraction or being multiplied.
She will need 9 computers. She has 8 groups of 3 and 1 group of 2. Therefore, she will need 9.
The answer to your question would be a cone
