Question

Square EFGH stretches vertically by a factor of 2.5 to create square E′F′G′H′. The square stretches with respect to the x-axis. If point H is located at (-2, 0), what are the coordinates of H′ ?

Answer 1

Given

Square EFGH stretches vertically by a factor of 2.5 to create square E′F′G′H

The square stretches with respect to the x-axis.

If point H is located at (-2, 0)

Find the coordinates of H′

To proof

In stretching case

when the stretching take place by scale fator

let coordinate = (x,y )

After stetching

new coordinate = ( kx,ky)

As given in question

Square EFGH stretches vertically by a factor of to create square E′F′G′H′= 2.5

square stretches with respect to the x-axis

coordinate of H = (-2,0)

coordinates of H′  = 2.5 (-2,0)

                               =  ( -5 , 0 )

Hence proved

Answer 2

The answer is B (-2, 0)