The answer would be 5/2q+9r+6r-20s
Explanation
We have the equation
5(1/2q+3r-4s)
which would equal
5/2q+15r-20s
so with the information
We can subtract 6r from 15r to get 9r
15r-6r=9r
+9r would be the missing piece
So we substitute it in to make the equation true.
5/2q(+9r)+6r-20s
Hope this helps or was correct
Answer:

Step-by-step explanation:
Since
, we need to find the hypotenuse given our corresponding opposite and adjacent lengths of -6 and -3 accounting for Quadrant III:

Thus, 
Answer:
no
Step-by-step explanation:
all integers are not real numbers.integers are negative and positive numbers. but real numbers don't include negative numbers.
Answer:
2^9x+3
Step-by-step explanation:
im not sure if this is correct i used photomath but idk if it understands the problem. you could try it on your actual paper with the writing correct instead of you hand typing the problem but i highly reccomend the app.