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stich3 [128]
3 years ago
6

Factoring trinomials,help?

Mathematics
1 answer:
borishaifa [10]3 years ago
6 0
Hey there!

When factoring trinomials, we're usually looking at the trinomial in the format of:

ax^2 + bx + c

In order to factor these, we have to use a different method than when a<1. When a is less than one, we can simply figure out the factors that add to the middle term and multiply to the last, but here we have to do a little something different.

The first step is to factor out the GCD of these terms. As you can see, there isn't one, as 13 is prime.

The next step is to multiply a by c:

6(6) = 36

Next, we have to, using the pattern of trinomials(the two binomials would have factors that add to the middle term and multiply to the last), we have to find factors of 36 that multiply to 36 and add to -13. When we do this step, we can disregard the last term for now. Let's list factors of 36:

36 =
18, 2 = 20
9,4 = 13
-9, -4 = 13
 
 -9 and -4 work for this. We can now write them as x terms and factor by grouping:

6m^2 - 4m - 9m + 6   (don't forget that last term)

For the left side, factor out a 2m:

2m(3m - 2)

For the right side, factor out a -3:

2m(m-2) - 3(m-2)

Now that we have our common factor of m-2, we can write them as a product of 2 binomials:

(2m-3)(m-2)

Hope this helps!

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3 years ago
A researcher is interested in the lengths of brook trout, which are known to be approximately Normally distributed with mean 80
aliya0001 [1]

Answer:

P(X

And we can find this probability with the normal standard distirbution or excel and we got:

P(z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the lenghts of a population, and for this case we know the distribution for X is given by:

X \sim N(80,5)  

Where \mu=80 and \sigma=5

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability with the normal standard distirbution or excel and we got:

P(z

6 0
3 years ago
8.) A line passes through the points (k, 4) and (3, -6). The line is perpendicular to
amm1812

Answer:

K = 43

Step-by-step explanation:

We'll begin by determining the gradient of the equation 5y + 4x = 8. This can be obtained as follow:

5y + 4x = 8

Rearrange

5y = 8 – 4x

5y = –4x + 8

Comparing 5y = –4x + 8 with y = mx + c, the gradient m is –4

Next, we shall determine the gradient of the line perpendicular to the line with equation 5y = 8 – 4x.

This can be obtained as follow:

For perpendicular lines, their gradient is given by:

m1 × m2 = – 1

With the above formula, we can obtain the gradient of the line as follow:

m1 × m2 = – 1

m1 = –4

–4 × m2 = – 1

Divide both side by –4

m2 = –1/–4

m2 = 1/4

Finally, we shall determine the value of k as follow:

Coordinate => (k, 4) and (3, –6)

x1 coordinate = k

y1 coordinate = 4

x2 coordinate = 3

y2 coordinate = –6

Gradient (m) = 1/4

m = (y2 – y1) / (x2 – x1)

1/4 = (–6 – 4) / (3 – K)

1/4 = –10 /(3 – K)

Cross multiply

3 – K = 4 × –10

3 – K = –40

Collect like terms

– K = – 40 –3

–k = –43

Divide both side by – 1

K = –43/–1

k = 43

3 0
3 years ago
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