A bag contains 4 red marbles and 2 white

Plzz hel am timed which number is composite

mezya [45]

15 is compostit bevuasw (3x5=15) (1x15)

8 0

3 years ago

A spring with a spring constant k of 100 pounds per foot is loaded with 1-pound weight and brought to equilibrium. It is then st

shutvik [7]

Answer:

Equation of movement y(t)

$y(t)=sin(10t-\pi/2)$

Amplitude: 1 inch

Period: 0.628 seconds

Step-by-step explanation:

If there is no friction, the amplitude will be the length it was streched from the equilibrium. In this case, this value is 1 inch

$A=1\,inch$

The period depends on the mass and the spring constant.

The formula for the period is:

$T=\frac{1}{f} =\frac{2/pi}{\omega} =2\pi\sqrt{\frac{m}{k}}=2\pi\sqrt{\frac{1}{100}}=2\pi*0.1=0.628\, s$

The model y(t) for the movement of the mass-spring system is

$y(t)=A\cdot sin(\omega t +\phi)\\\\A=1\\\\\omega=\sqrt{k/m} =\sqrt{100/1}=10\\\\y(0)=Asin(\phi)=-A\\\\ \phi=arcsin(-1)=-1.571=-\pi/2\\\\\\y(t)=sin(10t-\pi/2)$

8 0

3 years ago

Round 43.628 to the thousands place. A. 40.000 O O B. 43.000 O O C. 43.600 D. 44.000

VARVARA [1.3K]

Answer:

A) 40000

Step-by-step explanation:

this is the answer to your question

6 0

2 years ago

A student scored 66 points on his Psychology 101 midterm. If the average of his midterm and final must be between 78 and 90 incl

Paul [167]

Answer:

range of scores on final exam student get B is 90 to 100

Step-by-step explanation:

given data

Psychology 101 score = 66

average of his midterm = between 78 and 90

maximum = 100 points

to find out

range of scores on final exam student get B

solution

we consider here lowest marks need in final = x

so average at two marks should be

equation is

average marks = 0.5 × ( mid term marks + final marks ) .................1

put here value

78 = 0.5 × ( 66 + x )

x = 90

and

90 = 0.5 × ( 66 + x )

x = 114

so range 90 to 114

but maximum marks is 100 so

range of scores on final exam student get B is 90 to 100

3 0

3 years ago

2 points) Suppose w=xy+yzw=xy+yz, where x=et, y=2+sin(t)x=et, y=2+sin⁡(t), and z=2+cos(3t)z=2+cos⁡(3t). A ) Use the chain rule t

Olenka [21]

Answer:

$\frac{\partial w}{\partial t} = y(e^t) +(x+z)*(cos(t)) - 3y*sin(3t)$

Step-by-step explanation:

First, note that

$\frac{\partial x}{\partial t} = e^{t} \\\frac{\partial y}{\partial t} = cos(t)\\$

And using the chain rule in one variable

$\frac{\partial z}{\partial t} = -3sin(3t)$

Now remember that the chain rule in several variables sates that

$\frac{\partial w}{\partial t} = \frac{\partial w}{\partial x} * \frac{\partial x}{\partial t} + \frac{\partial w}{\partial y} * \frac{\partial y}{\partial t} + \frac{\partial w}{\partial z} * \frac{\partial z}{\partial t}$

Therefore the chain rule in several variables would look like this.

$\frac{\partial w}{\partial t} = y(e^t) +(x+z)*(cos(t)) - 3y*sin(3t)$

6 0

3 years ago

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