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LUCKY_DIMON [66]
3 years ago
5

What is the following product? 3√16x^7 3√12x^9 Please help, Thank you!

Mathematics
2 answers:
jeyben [28]3 years ago
7 0

Answer:

Product of cube root of :

\sqrt[3]{16x^7} \times \sqrt[3]{12x^9}

First simplify :\sqrt[3]{16x^7}

Factor: One of two or more expressions that are multiplied together to get a product

then, we can write it as:

\sqrt[3]{2 \cdot 8 x^7} ,

Rewrite 8 as 2^3 and x^7 = x^6 \cdot x

\sqrt[3]{2\cdot 2^3 \cdot x^6 \cdot x} or

\sqrt[3]{2\cdot 2^3 \cdot (x^2)^3 \cdot x}       [∵ (a^x)^y=a^{xy} ]

or  \sqrt[3]{2^3 \cdot (x^2)^3 \cdot 2\cdot x}

or 2 \cdot x^2\sqrt[3]{2\cdot x}     [∵\sqrt[3]{a^3} =a ]

Similarly, we simplify for \sqrt[3]{12 x^9}

Then, we can write it as \sqrt[3]{12\cdot (x^3)^3}  or

x^3 \cdot \sqrt[3]{12}

Use : x^{a+b}=x^a \cdot x^b , \sqrt[3]{a} \cdot\sqrt[3]{b} = \sqrt[3]{a \cdot b}

Now,

\sqrt[3]{16x^7} \times \sqrt[3]{12x^9} = 2 \cdot x^2\sqrt[3]{2\cdot x} \times x^3 \cdot \sqrt[3]{12}

= 2x^2 \cdot x^3 \sqrt[3]{2x} \cdot \sqrt[3]{12}

= 2 x^5\cdot \sqrt[3]{2x \cdot 12} or 2x^5 \cdot \sqrt[3]{24 x}

= 2x^5 \cdot \sqrt[3]{8 \cdot 3x} or 2 x^5 \cdot \sqrt[3]{2^3 \cdot 3 \cdot x}

= 2x^5 \cdot 2 \sqrt[3]{3x} = 4 x^5 \cdot \sqrt[3]{3x}

therefore, the product of  \sqrt[3]{16x^7} \times \sqrt[3]{12x^9} is,  4 x^5 \cdot \sqrt[3]{3x}








ira [324]3 years ago
5 0

\displaystyle\sqrt[3]{16x^7}\times\sqrt[3]{12x^9}=\sqrt[3]{16\cdot 12x^{(7+9)}}\\\\=\sqrt[3]{4^3\cdot 3x^{16}}=\sqrt[3]{\left(4x^5\right)^3\cdot 3x}\\\\=4x^5\sqrt[3]{3x}

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