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MariettaO [177]
3 years ago
15

Write in factored form: 13x - 26

Mathematics
2 answers:
iogann1982 [59]3 years ago
6 0
Factored form is x-2
erica [24]3 years ago
6 0


Take out a common factor

13(x-2)

you cant factor any further

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The volume of a volleyball is about 288 cubic inches. what is the radius of the volleyball, to the nearest tenth of an inch? use
Len [333]

Answer:

The radius of the volleyball is 8.3 inches

Step-by-step explanation:

Given

r = \sqrt{\frac{3v}{4\pi}}

v = 288

Required

Determine the value of r

To do this, we simply substitute 288 for v and 3.14 for π in the given equation.

This gives

r = \sqrt{\frac{3v}{4\pi}}

r = \sqrt{\frac{3 * 288}{4 * 3.14}}

r = \sqrt{\frac{864}{12.56}}

r = \sqrt{68.7898089172}

r = 8.29396219651

r = 8.3\ inch (Approximated)

Hence;

<em>The radius of the volleyball is 8.3 inches</em>

3 0
3 years ago
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If k(x) = 2x² -3.Vx, then k(9) is
Alexus [3.1K]

Answer:

159

Step-by-step explanation:

k (9) = (2 * 9^{2}) - 3

= (2 * 81) - 3

= 162 - 3

= 159

8 0
3 years ago
The sum of the number times 3 and 15​
Anon25 [30]

Answer:

45 should be the answer

3 0
3 years ago
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In order to estimate the average time spent on the computer terminals per student at a local university, data were collected fro
Ksju [112]

Answer:

d. 0.133

Step-by-step explanation:

-Standard error is  calculated using the formula:

E=\frac{\sigma}{\sqrt{n}}\\\\\sigma-=standard \ deviation\\n=sample \ size

#We substitute the given values in the formula to solve for E:

E=\frac{\sigma}{\sqrt{n}}\\\\=\frac{1.2}{\sqrt{81}}\\\\=0.133

Hence, the standard error is 0.133 and the correct option is d

7 0
3 years ago
Suppose that an airline uses a seat width of 16.7 in. Assume men have hip breadths that are normally distributed with a mean of
murzikaleks [220]

Answer:

Step-by-step explanation:

Given that X, the hip width of men is N(14.2, 0.9)

i.e. we have \frac{x-14.2}{0.9} is N(0,1)

Seat width an airline uses = 16.7 inches.

a) the probability that if an individual man is randomly selected, his hip breadth will be greater than 16.7 in

=P(X>16.7 inches)\\= P(Z>\frac{16.7-14.2}{0.9} =P(Z>2.77)\\\\\\=P(Z>0)-(0

b) Here sample size = 126

Each person is independent of the other

the probability that these men have a mean hip breadth greater than 16.7

=0.0028^{126} <0.00001

c) part a is important since even a single person not fitting will cause embarassment and leads to customer dissatisfaction.

5 0
3 years ago
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