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Alex787 [66]
3 years ago
12

Using two normal dice, what is the probability of rolling numbers that add up to 3?

Mathematics
1 answer:
Blizzard [7]3 years ago
4 0
That would be rolling a 1 and a 2 .

so possibilities are 1 on first die and 2 on the second die

OR 2 on first die and 1 on the second.

Both of these have a probability of 1/6 * 1/6 = 1/36

so required probability = 1/36 + 1/36 = 2/36 = 1/18


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A large electronic office product contains 2000 electronic components. Assume that the probability that each component operates
KIM [24]

Answer:

The probability is 0.971032

Step-by-step explanation:

The variable that says the number of components that fail during the useful life of the product follows a binomial distribution.

The Binomial distribution apply when we have n identical and independent events with a probability p of success and a probability 1-p of not success. Then, the probability that x of the n events are success is given by:

P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}

In this case, we have 2000 electronics components with a probability 0.005 of fail during the useful life of the product and a probability 0.995 that each component operates without failure during the useful life of the product. Then, the probability that x components of the 2000 fail is:

P(x)=\frac{2000!}{x!(2000-x)!}*0.005^{x}*(0.995)^{2000-x}     (eq. 1)

So, the probability that 5 or more of the original 2000 components fail during the useful life of the product is:

P(x ≥ 5) = P(5) + P(6) + ... + P(1999) + P(2000)

We can also calculated that as:

P(x ≥ 5) = 1 - P(x ≤ 4)

Where P(x ≤ 4) = P(0) + P(1) + P(2) + P(3) + P(4)

Then, if we calculate every probability using eq. 1, we get:

P(x ≤ 4) = 0.000044 + 0.000445 + 0.002235 + 0.007479 + 0.018765

P(x ≤ 4) = 0.028968

Finally, P(x ≥ 5) is:

P(x ≥ 5) = 1 - 0.028968

P(x ≥ 5) = 0.971032

3 0
3 years ago
Which of this is/are true? i: 11>9 ii. -11 > -3 iii.6-3 <-2
Ymorist [56]
11>9 this is the answer
4 0
3 years ago
Please help due in a few minutes I will mark u brainliest
Goryan [66]

Answer:

y=4x-5

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Write the Roman Numeral CLXIV in standard form. Roman Numeral Standard Number 1 5 10 50 100 500 1,000 X L C D A) 169 B) 166 C) 1
elena-14-01-66 [18.8K]

Answer:

164

Step-by-step explanation:

in standard form CLXIV IS 164

5 0
2 years ago
44 ÷ 1100<br> pls show your work thx
mestny [16]

Answer:

25 is the answer

for proof see the pic

<em>first divide it by 11 then and when you get the numerator as 100 and denominator as 4 divide it by 2</em>

So as to get numerator as 50 and denominator as 2 .

<em>L</em><em>a</em><em>t</em><em>e</em><em>r</em><em>,</em><em> </em><em>D</em><em>i</em><em>v</em><em>i</em><em>d</em><em>e</em><em> </em><em>i</em><em>t</em><em> </em><em>b</em><em>y</em><em> </em><em>2</em><em> </em><em>a</em><em>n</em><em>d</em><em> </em><em>h</em><em>e</em><em>n</em><em>c</em><em>e</em><em>,</em><em> </em><em>y</em><em>o</em><em>u</em><em>r</em><em> </em><em>a</em><em>n</em><em>s</em><em>w</em><em>e</em><em>r</em><em> </em><em>i</em><em>s</em><em> </em><em>2</em><em>5</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>;</em><em>)</em>

5 0
3 years ago
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