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3 years ago

14

Please help!! What is the slope of the line?

2 answers:

Usimov [2.4K]3 years ago

3 0

Do you have A picture of the line?

uranmaximum [27]3 years ago

3 0

We need a picture to know help you

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Aldo put $400 into a savings account that paid an interest rate of 5.4% per year. What was the total amount in his account at th

Greeley [361]

Aldo had $421.60 in his account at the end of 1 year. 400 x 5.4% = $21.6 in interest from one year. $400 + $21.60 = $421.60

3 0

4 years ago

PLEASE HELP WILL MARK BEST!

Veronika [31]

Answer:

I think the answer is 5,000 .

4 0

3 years ago

Angle ABD measures (4x + 10)o. Angle ACD measures (5x − 2)o.

melamori03 [73]

Answer:

96°

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

This figure is made up of a quadrilateral and a semicircle.

vodomira [7]

Here the figure is made up of a quadrilateral and a semi circle.

ABCD is the quadrilateral here. We will find the sides of the quadrilateral by using the distance formula.

If (x₁, y₁) and (x₂, y₂) are two points given, then the distance between two points by using distance formula is,

$d =\sqrt({ x_{1}-x_{2})^2 +( y_{1} -y_{2} )^2}$

The co-ordinate of A is (-1,2) and co-ordinate of B is (-2,-1).

So the length of side AB = $\sqrt{(-1-(-2))^2+(2-(-1))^2}$

= $\sqrt{(-1+2)^2+(2+1)^2}$ (As negative times negative is positive)

= $\sqrt{(1)^2+(3)^2} =\sqrt{1+9} =\sqrt{10}$

The co-ordinate of C is (4,-3) and D is (5,0)

The length of side CD

= $\sqrt(4-5)^2+(-3-0)^2}$

= $\sqrt{(-1)^2+(-3)^2}$

= $\sqrt{1+9} =\sqrt{10}$

So the sides AB and CD are equal.

The length of side AD

= $\sqrt{(-1-5)^2+(2-0)^2}$

= $\sqrt{(-6)^2+(2)^2} =\sqrt{36+4} =\sqrt{40}$

The length of side BC

= $\sqrt{(-2-4)^2+(-1-(-3))^2}$

= $\sqrt{(-2-4)^2+(-1+3)^2}$

= $\sqrt{(-6)^2+(2)^2}=\sqrt{36+4} =\sqrt{40}$

So the lengths of the sides AD and BC are equal.

So the quadrilateral is a rectangle whose length is $\sqrt{40}$ and width is $\sqrt{10}$ .

Area of a rectangle = length × width

= $(\sqrt{40}) (\sqrt{10})$

= $\sqrt{(40)(10)}=\sqrt{400}$

= $20 unit^2$

Now the diameter of the semicircle is the side AD = $\sqrt{40}$

So, the radius of the semi-circle = $\frac{\sqrt{40}}{2}$

= $\frac{\sqrt{(4)(10)}}{2}$

= $\frac{(\sqrt{4})(\sqrt{10})}{2}$

= $\frac{2\sqrt{10}}{2}$ = $\sqrt{10}$

Area of semi-circle = $\frac{1}{2} \pi r^2$ , where r is the radius.

= $\frac{1}{2} \pi (\sqrt{10})^2$

= $\frac{1}{2} \pi (10)$

= $\frac{(\pi)(10)}{2}$

= $\frac{10\pi}{2} = 5\pi$ = $15.7 unit^2$ ( Approximately taken to the nearest tenth)

Total area of the figure = $(20+15.7) unit^2$ = $35.7 unit^2$

We have got the required answer.

Option a is correct here.

3 0

3 years ago

Read 2 more answers

The table shows a relationship between the number of pounds of apples and the total cost. Is the relationship proportional?

Mice21 [21]

Answer:

C Yes, because the cost is always three times the number of pounds.

Step-by-step explanation:

Because 2*3=6, 4*3=12, and 8*3=24

7 0

2 years ago