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Georgia [21]
3 years ago
7

1/2(-10x+4)= -4(-3+2x)+8

Mathematics
1 answer:
bezimeni [28]3 years ago
8 0

Answer:

6 is the answer

Step-by-step explanation:

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In calculating interest by the previous balance method, purchases and payments during the month _____ counted in calculation of
anyanavicka [17]
In calculating interest by the previous balance method, purchases and payments during the month are not counted in calculation of interest.
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3 years ago
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Simplify the expression <img src="https://tex.z-dn.net/?f=-%5Cfrac%7B4x%2B7%7D%7B2%7D%20-%5Cfrac%7B3x-2%7D%7B2%7D" id="TexFormul
ExtremeBDS [4]

Answer:

-(4x + 7)/2 - (3x - 2)/2 = (-4x - 7 - 3x + 2)/2 = (-7x - 5)/2

8 0
4 years ago
A recursive rule for a geometric sequence is
LuckyWell [14K]

Answer:

C. a_n=(9)(\frac{2}{3})^{n-1}

Step-by-step explanation:

Iterative geometric sequence:

a_n=a_1x^{n-1}

Recursive geometric sequence:

a_n=xa_{n-1}

The equations are very similar and you only really need to rearrange it. The factor (2/3) and the first term (9) are given, so you can write the iterative equation:

a_n=(9)(\frac{2}{3})^{n-1}

And so the answer is C.

5 0
2 years ago
Find the annual rate of interest. Principal = 4600 rupees Period = 5 years Total amount = 6440 rupees Annual rate of interest =
Semmy [17]

Answer:

The rate of interest for compounded annually is 6.96 %  .

Step-by-step explanation:

Given as :

The principal amount = Rs 4600

The time period = 5 years

The amount after 5 years = Rs 6440

Let The rate of interest = R %

<u>From compounded method</u>

Amount = Principal × (1+\dfrac{\textrm rate}{100})^{\textrm Time}

or, Rs 6440 = Rs 4600 × (1+\dfrac{\textrm R}{100})^{\textrm 5}

Or, \frac{6440}{4600} =  (1+\dfrac{\textrm R}{100})^{\textrm 5}

or, 1.4 =  (1+\dfrac{\textrm R}{100})^{\textrm 5}

Or, (1.4)^{\frac{1}{5}} = 1 + \dfrac{R}{100}

or, 1.0696 =  1 + \dfrac{R}{100}

or, \dfrac{R}{100} = 1.0696 - 1

Or, \dfrac{R}{100} = 0.0696

∴ R = 0.0696 × 100

I.e R = 6.96

Hence The rate of interest for compounded annually is 6.96 %  .  Answer

5 0
3 years ago
Suppose a triangle has two sides of length 32 and 35, and that the angle
pantera1 [17]

Answer:

The third side is around 58.043

Step-by-step explanation:

Use the law of cosines:  c^2=a^2+b^2-2abcos(C)

Plug in the two sides we know (into a and b) and the angle we know (into angle C).

Thus:

c^2=32^2+35^2-2(32)(35)cos(120)

Use a calculator:

c^2=3369\\

c=58.043087...

(Note: Make sure you're in Degrees mode.)

3 0
3 years ago
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