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3 years ago

Suppose f(x)=x^2 and g(x)= 4x^2.Which statement best compares the graph of g(x) with the graph of f(x)?

Mathematics

1 answer:

professor190 [17]3 years ago

4 0

Answer:

They are both quadratic functions

Step-by-step explanation:

In the equation of both f(x) and g(x), the x is being powered by 2 (squared) which makes them both a quadratic function.

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There are five consecutive even integers. The sum of the first two is thirty-six less than the sum of the last three numbers. Wh

Norma-Jean [14]

5 consecutive even integers: 2n, 2n+2, 2n+4, 2n+6, 2n+8 for any integer n The sum of the two smallest of five consecutive even integers is 50 less than the sum of the other three integers: 2n + 2n+2 = 2n+4 + 2n+6 + 2n+8 - 504n + 2 = 6n -3234 = 2nn = 17 The smallest integer in our sequence is 2n = 2*17 = 34 Check:2n + 2n+2 = 2n+4 + 2n+6 + 2n+8 - 5034 + 36 = 38 + 40 + 42 - 5070 = 120 - 5070 = 70

6 0

3 years ago

What is the slope of the line y = 6x + 3? 3 -6 6 -3

Nataly_w [17]

Answer:

the answer is 6

Step-by-step explanation:

slope = m

y = mx + c

m = 6

8 0

2 years ago

16.8 - (-23.72)+(-31.3) = x

KatRina [158]

Let's solve your equation step-by-step

16.8-(-23.72)-31.3=x

Step 1:simplify both sides of the equation

16.8-(-23.72)-31.3=x

16.8+23.72+-31.3=x

(16.8+23.72+-31.3)=x (combine like terms)

9.22=x

Step 2: flip the equation

Answer: x=9.22

5 0

3 years ago

What is the fourth term in the binomial expansion (a+b)^6)

Dafna11 [192]

Answer:

$20a^3b^3$

Step-by-step explanation:

Binomial Series

$(a+b)^n=a^n+\dfrac{n!}{1!(n-1)!}a^{n-1}b+\dfrac{n!}{2!(n-2)!}a^{n-2}b^2+...+\dfrac{n!}{r!(n-r)!}a^{n-r}b^r+...+b^n$

Factorial is denoted by an exclamation mark "!" placed after the number. It means to multiply all whole numbers from the given number down to 1.

Example: 4! = 4 × 3 × 2 × 1

Therefore, the fourth term in the binomial expansion (a + b)⁶ is:

$\implies \dfrac{n!}{3!(n-3)!}a^{n-3}b^3$

$\implies \dfrac{6!}{3!(6-3)!}a^{6-3}b^3$

$\implies \dfrac{6!}{3!3!}a^{3}b^3$

$\implies \left(\dfrac{6 \times 5 \times 4 \times \diagup\!\!\!\!3 \times \diagup\!\!\!\!2 \times \diagup\!\!\!\!1}{3 \times 2 \times 1 \times \diagup\!\!\!\!3 \times \diagup\!\!\!\!2 \times \diagup\!\!\!\!1}\right)a^{3}b^3$

$\implies \left(\dfrac{120}{6}\right)a^{3}b^3$

$\implies 20a^3b^3$

7 0

1 year ago

The clock was exactly on time at 7am at 1pm the clock was 228 seconds late at that rate how slow was the clock half an hour

yan [13]

Answer:

19 seconds.

Step-by-step explanation:

Given that the clock was exactly on time at 7am, and at 1pm the clock was 228 seconds late, to determine, at that rate, how slow was the clock half an hour, the following calculation must be performed:

1 PM = 13:00

13 - 7 = 6

228/6 = 38

38/2 = 19

Thus, every half hour the clock is delayed 19 seconds.

4 0

2 years ago