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ankoles [38]
3 years ago
12

9 stores is 3% of how many stores

Mathematics
2 answers:
vladimir1956 [14]3 years ago
6 0
This question is a little tricky.  This means that 9 is 3% of x stores.  3% is equal to 0.03, because a percent is a hundredth of a whole.  To find the percentage of x stores, we multiply the percent (in decimal form) by x.  This is equal to 9.  Our equation is 9=0.03x.  Now, all we have to do is divide 9 by 0.03, to isolate x, and we'll know the answer!  9/0.03=0.03x/0.03.  9/0.03=300.  So, x=300.

Answer: 300 stores
k0ka [10]3 years ago
4 0
Hey There!

The answer to this problem is 2.7

Steps
1. Multiply 9*0.3

2. Once you multiply you should get 2.7

3. To solve step one you have to  pretend you are multiplying 9*3

4. The answer you get for step 3 is 27

5. After you get that answer (27) you must put the decimal in

6. After you do step 5 you should get 2.7

In conclusion, you're final answer should be 2.7

Hope This Helped ;)
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Use the given equation to find the number<br><br> 1/2x-19.7=-4.1
Leokris [45]

Answer:

the number is 31.2

Step-by-step explanation:

Given that:

1/2x-19.7=-4.1

Adding 19.7 on both sides:

1/2x-19.7 + 19.7=-4.1 + 19.7

1/2x = 15.6

Multiplying both sides by 2:

x = 15.6 * 2

x = 31.2

So the number is 31.2

i hope it will help you!

7 0
3 years ago
Help I am very bad at math I need answers by tomorrow if you can help please do​
d1i1m1o1n [39]

Answer:

Step-by-step explanation:

(a - b)(a +b) = a² - b²

1 - Sin² A = Cos² A

LHS = \frac{1}{1- Sin A} + \frac{1}{1 + Sin A}\\\\= \frac{1*(1 + Sin A)}{(1- Sin A)(1 + Sin A)} + \frac{1*(1- Sin A)}{(1 + Sin A)(1- Sin A)}\\\\= \frac{1 + Sin A+ 1 - Sin A}{1^{2}-  Sin^{2} A}\\\\= \frac{2}{1 - Sin^{2} A}\\\\= \frac{2}{Cos^{2} A}\\\\= 2 Sec^{2} A

2)  Sec² A - Tan² A = 1

LHS = \frac{1}{Sec A - Tan A}\\\\=\frac{1*(Sec A + Tan A)}{(Sec A -  Tan A)(Sec A + Tan A)}\\\\=\frac{Sec A + Tan A}{Sec^{2} A - Tan^{2} A}\\\\=\frac{Sec A + Tan A }{1}\\\\= Sec A + Tan A = RHS\\\\\\

3) LHS  = Cosec² A + Cot² A

             = Cosec² A +  Cosec² A - 1

            = 2Cosec² A - 1   = RHS

4) LHS = \frac{Sec A}{Cos A}- \frac{Tan A}{Cot A}\\\\          = Sec A*\frac{1}{Cos A}-Tan A*\frac{1}{Cot A}\\\\ = Sec A * Sec A - Tan A * Tan A\\\\= Sec^{2} A - Tan^{2} A \\\\= 1

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Answer:

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Step-by-step explanation:

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