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3 years ago

Sophia has $8 to spend on lunch. Does she have enough money for a sandwich, drink and a bag of chips? Sandwich:$4

2 answers:

8 0

To find out if Sophia has enough money for a sandwich, drink, and chips, add the price of the food and see if it is more than 8. A sandwich costs 4, a drink costs 2, and chips cost 1. Add them together. 4+2+1 = 7. It costs $7 and Sophia has $8. She has enough.

makkiz [27]3 years ago

6 0

Yes she has enough to cover all 3 items, with a dollar left over

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What are the domain and range of f(x) = |x – 3 | + 6? Domain: {x | x is all real numbers} Range: {y | y ≥ 6} Domain: {x | x ≥ 3}

VARVARA [1.3K]

Answer:

Domain: {x | x is all real numbers} Range: {y | y ≥ 6}

Step-by-step explanation:

Domain is the set of all x values. No operations restrict the domain in this case. The domain is all real numbers.

Range is the set of all y values. Absolute value has a v shape starting at 0. Adding 6 raises this vertex to 6. The range is therefore all numbers greater than or equal to 6.

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3 years ago

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cupoosta [38]

Answer:

3/5 or 0.6

Step-by-step explanation:

Here, given the value of tan theta , we want to find the value of sine theta

Mathematically;

tan theta = 0pposite/adjacent

Sine theta = opposite/hypotenuse

Firstly we need the length of the hypotenuse

This can be obtained using the Pythagoras’ theorem which states that the square of the hypotenuse equals sum of the squares of the two other sides.

Let’s call the hypotenuse h

h^2 = 3^2 + 4^2

h^2 = 9 + 16

h^2 = 25

h = √(25)

h = 5

Now from the tan theta, we know that the opposite is 3

Thus, the value of the sine theta = 3/5 or simply 0.6

5 0

3 years ago

The total monthly profit for a firm is P(x)=6400x−18x^2− (1/3)x^3−40000 dollars, where x is the number of units sold. A maximum

wlad13 [49]

Answer:

Maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

Step-by-step explanation:

We are given the following information: $P(x) = 6400x - 18x^2 - \frac{x^3}{3} - 40000$ , where P(x) is the profit function.

We will use double derivative test to find maximum profit.

Differentiating P(x) with respect to x and equating to zero, we get,

$\displaystyle\frac{d(P(x))}{dx} = 6400 - 36x - x^2$

Equating it to zero we get,

$x^2 + 36x - 6400 = 0$

We use the quadratic formula to find the values of x:

$x = \displaystyle\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}$ , where a, b and c are coefficients of $x^2, x^1 , x^0$ respectively.

Putting these value we get x = -100, 64

Now, again differentiating

$\displaystyle\frac{d^2(P(x))}{dx^2} = -36 - 2x$

At x = 64, $\displaystyle\frac{d^2(P(x))}{dx^2} < 0$

Hence, maxima occurs at x = 64.

Therefore, maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

6 0

3 years ago

If grapes cost .95 per 500 grams how much would 800 grams cost

nevsk [136]

500g = $0.95

100g = $0.95 ÷ 5 = $0.19

800g = $0.19 x 8 = $1.52

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Answer: 800g will cost $1.52
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7 0

3 years ago