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iogann1982 [59]
3 years ago
6

Sophia has $8 to spend on lunch. Does she have enough money for a sandwich, drink and a bag of chips? Sandwich:$4

Mathematics
2 answers:
zheka24 [161]3 years ago
8 0
To find out if Sophia has enough money for a sandwich, drink, and chips, add the price of the food and see if it is more than 8. A sandwich costs 4, a drink costs 2, and chips cost 1. Add them together. 4+2+1 = 7. It costs $7 and Sophia has $8. She has enough.
makkiz [27]3 years ago
6 0
Yes she has enough to cover all 3 items, with a dollar left over
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Need help!!!!!!!!!!!!!
xeze [42]

Answer:

m = $14/day

w = $6/day

Step-by-step explanation:

See attached image.

7 0
2 years ago
Problem Situation: Ben buys a table for $240. He also buys 6 chairs that all cost the same amount. His total cost is $720. What
butalik [34]

Answer:

80 Dollars per chair

Step-by-step explanation:

Step One:

Subtract 720 by (-) 240

this should give you, 480

Step Two:

Divide 480 by 6

Which gives you your answer 80

5 0
2 years ago
The difference of two numbers is equal to 0.6. Their quotient is also 0.6. What are the numbers? There are 4
Makovka662 [10]
Let the two numbers be represented by x and y. The problem statement gives rise to two sets of equations.
  x - y = 0.6
  y/x = 0.6 . . . . . . . assuming x is the larger of the two numbers
or
  x/y = 0.6 . . . . . . . assuming y has the larger magnitude

The solution of the first pair of equations is
  (x, y) = (1.5, 0.9)

The solution of the first and last equations is
  (x, y) = (-0.9, -1.5)

The pairs of numbers could be {0.9, 1.5} or {-1.5, -0.9}.
8 0
3 years ago
F(x) = x2 − x − ln(x) (a) find the interval on which f is increasing. (enter your answer using interval notation.) find the inte
Mekhanik [1.2K]

Answer:

(a) Decreasing on (0, 1) and increasing on (1, ∞)

(b) Local minimum at (1, 0)

(c) No inflection point; concave up on (0, ∞)

Step-by-step explanation:

ƒ(x) = x² - x – lnx

(a) Intervals in which ƒ(x) is increasing and decreasing.

Step 1. Find the zeros of the first derivative of the function

ƒ'(x) = 2x – 1 - 1/x = 0

           2x² - x  -1 = 0

     ( x - 1) (2x + 1) = 0

         x = 1 or x = -½

We reject the negative root, because the argument of lnx cannot be negative.

There is one zero at (1, 0). This is your critical point.

Step 2. Apply the first derivative test.

Test all intervals to the left and to the right of the critical value to determine if the derivative is positive or negative.

(1) x = ½

ƒ'(½) = 2(½) - 1 - 1/(½) = 1 - 1 - 2 = -1

ƒ'(x) < 0 so the function is decreasing on (0, 1).

(2) x = 2

ƒ'(0) = 2(2) -1 – 1/2 = 4 - 1 – ½  = ⁵/₂

ƒ'(x) > 0 so the function is increasing on (1, ∞).

(b) Local extremum

ƒ(x) is decreasing when x < 1 and increasing when x >1.

Thus, (1, 0) is a local minimum, and ƒ(x) = 0 when x = 1.

(c) Inflection point

(1) Set the second derivative equal to zero

ƒ''(x) = 2 + 2/x² = 0

             x² + 2 = 0

                   x² = -2

There is no inflection point.

(2). Concavity

Apply the second derivative test on either side of the extremum.

\begin{array}{lccc}\text{Test} & x < 1 & x = 1 & x > 1\\\text{Sign of f''} & + & 0 & +\\\text{Concavity} & \text{up} & &\text{up}\\\end{array}

The function is concave up on (0, ∞).

6 0
3 years ago
write a equation in slope-intercept form for the line that is parallel to y=2x-8 and passes through the point(1,5).
Brilliant_brown [7]

Answer:

y = 2x + 3

Step-by-step explanation:

y = 2x - 8   passes through ( 1,5 )

y = 2x + 3 is parallel to y = 2x - 8 because it has the same m( 2x)

and it also passes through ( 1, 5 )

Try Desmos, very helpful

Hope this helps

7 0
3 years ago
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