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ValentinkaMS [17]
3 years ago
9

Which equation is graphed here?

Mathematics
2 answers:
evablogger [386]3 years ago
5 0
I think the answer here is a
zloy xaker [14]3 years ago
5 0

Answer:

A) y+5=-3/2(x-4)

Step-by-step explanation:

Start by rewriting the equation A into slope intercept form (y=mx+b).

1) Distribute the -3/2 to x and -4:

y+5=-3/2x+6

2) Subtract 5 from both sides:

y=-3/2x+1

Now lets check to see if the equation matches up with the line...

The slope (-3/2) is correct, because every time you go down three, you go across to the right 2!

We also know the y intercept, (1) is correct, because the line crosses the y axis at the point (0,1)

Therefore, the correct answer is A!

You might be interested in
sydney planted 5/9 of her fall flowers.she had 63 unplanted flowers to start.how many flowers does she have left to plant.?how m
PilotLPTM [1.2K]
35. 

5/9= 0.555555556

0.55555556*63=35

2/3= 0.6666666667

0.666666667*63= 42

63-35=28

42-28=14
She has 35 unplanted flowers and must plant 14 more in order to have filled 2/3 of her flower bed. 




8 0
3 years ago
A square has an area of 9 cm². Find its perimeter
dlinn [17]

Answer:

12

Step-by-step explanation:

area is base x height. 3×3 is 9. all sides of a square are equal so 3+3+3+3= the perimeter which is 12.

8 0
2 years ago
Read 2 more answers
-1/4x – 2/3x = -6 + 28
77julia77 [94]

Answer:

x= -24

Step-by-step explanation:

-1/4x-2/3x= -6+28

add -6 to 28 but since 6 is a negative its subtraction

-1/4x-2/3x=22

multiply all by 12

-3x-8x=264

add -3x to -8x

-11x=264

divide both sides by -11

x= -24

3 0
3 years ago
Do you think making a table is the best way to find the total area of the rooms given in the example?
atroni [7]
Yes I would say. if I am wrong I am sorry
8 0
3 years ago
How would you determine the axis of symmetry in order to graph x^2 = 8y^2.
Tanya [424]
The picture illustrates the definition. The point P is a typical point on the parabola so that its distance from the directrix, PQ, is equal to its distance from F, PF. The point marked V is special. It is on the perpendicular line from F to the directix. This line is called the axis of symmetry of the parabola or simply the axis of the parabola and the point V is called the vertex of the parabola. The vertex is the point on the parabola closest to the directrix.

Finding the equation of a parabola is quite difficult but under certain cicumstances we may easily find an equation. Let's place the focus and vertex along the y axis with the vertex at the origin. Suppose the focus is at (0,p). Then the directrix, being perpendicular to the axis, is a horizontal line and it must be p units away from V. The directrix then is the line y=-p. Consider a point P with coordinates (x,y) on the parabola and let Q be the point on the directrix such that the line through PQ is perpendicular to the directrix. The distance PF is equal to the distance PQ. Rather than use the distance formula (which involves square roots) we use the square of the distance formula since it is also true that PF2 = PQ2. We get

<span>(x-0)2+(y-p)2 = (y+p)2+(x-x)2. 
x2+(y-p)2 = (y+p)2.</span>If we expand all the terms and simplify, we obtain<span>x2 = 4py.</span>

Although we implied that p was positive in deriving the formula, things work exactly the same if p were negative. That is if the focus lies on the negative y axis and the directrix lies above the x axis the equation of the parabola is

<span>x2 = 4py.</span><span>The graph of the parabola would be the reflection, across the </span>x<span> axis of the parabola in the picture above. A way to describe this is if p > 0, the parabola "opens up" and if p < 0 the parabola "opens down".</span>

Another situation in which it is easy to find the equation of a parabola is when we place the focus on the x axis, the vertex at the origin and the directrix a vertical line parallel to the y axis. In this case, the equation of the parabola comes out to be

<span>y2 = 4px</span><span>where the directrix is the verical line </span>x=-p and the focus is at (p,0). If p > 0, the parabola "opens to the right" and if p < 0 the parabola "opens to the left". The equations we have just established are known as the standard equations of a parabola. A standard equation always implies the vertex is at the origin and the focus is on one of the axes. We refer to such a parabola as a parabola in standard position.

Parabolas in standard positionIn this demonstration we show how changing the value of p changes the shape of the parabola. We also show the focus and the directrix. Initially, we have put the focus on the y axis. You can select on which axis the focus should lie. Also you may select positive or negative values of p. Initially, the values of p are positive. 

5 0
3 years ago
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