Answer:
lateral area = 2320 m²
Step-by-step explanation:
The question wants us to calculate the lateral area of a square base pyramid. The square base pyramid has a side of 40 meters.The height is 21 meters.
Half of the square base is 40/2 = 20 meters . With the height it forms a right angle triangle. The hypotenuse side is the slant height of the pyramid.
Using Pythagoras's theorem
c² = a² + b²
c² = 20² + 21²
c² = 400 + 441
c² = 841
square root both sides
c = √841
c = 29 meters
The slant height of the pyramid is 29 meters.
The pyramid has four sided triangle. The lateral area is 4 multiply by the area of one triangle.
area of triangle = 1/2 × base × height
base = 40 meters
height = 29 meters
area = 1/2 × 40 × 29
area = 580
area of one triangle = 580 m²
Lateral area = 4(580)
lateral area = 2320 m²
Answer:
x = -6
Explanation:
Simplify
1/14x + 10/7 = 1
Subtract 10/7 from both sides
1/14x + 10/7 - 10/7 = 1 - 10/7
1/14x = -3/7
Multiply both sides by 14
1/14x*14 = -3/7*14
x = -6
Answer:
4/12 = 1/3
Step-by-step explanation:
Mike - Brent
11/12 - 7/12
4/12
then simplify:- 1/3
3.6 x 3.4.
6 times 4 is 24 so carry the 2. next 4 times 3 is 12 then add the so 14.
Next you do the left side; 3 times 3 is 9.. then 3 times 6 is equals 18.
Now u should have 144 on top and 189 you add those; which equals 333. In each number (3.6 and 3.4); the decimal moved over once so 1 times 2 = 2
so move the decimal over twice and the answer would be 3.33
25 = 5 x 5
48 = 6 x 8 = 2 x 3 x 2 x 2 x 2
52 = 4 x 13 = 2 x 2 x 13
33 = 3 x 11
46 = 2 x 23