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4 years ago

1/3 ton to the nearest pound

1 answer:

8 0

First you need to know what system is being used. the us system uses what is called a short ton which is 2000 lbs

the british tend to use the long ton which is 2240 lbs. 

1/3 short ton = 666.66 lbs 
1/3 long ton = 746.59 lbs

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What is the total perimeter of this figure? Express your answer in feet.

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4 years ago

What is 4/6 x 5/6 = plz help i need to pass my math

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3 years ago

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Express .32 as a fraction

nikdorinn [45]

Answer: 8/25

Step-by-step explanation: Using the place value chart, we can see that the decimal 0.32 is thirty-two hundredths so we can write 0.32 as 32/100.

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This means that 0.32 can be written as the fraction 8/25 which is in lowest terms.

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3 years ago

A cylindrical can without a top is made to contain 25 3 cm of liquid. What are the dimensions of the can that will minimize the

Basile [38]

Answer:

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

Step-by-step explanation:

Given that, the volume of cylindrical can with out top is 25 cm³.

Consider the height of the can be h and radius be r.

The volume of the can is V= $\pi r^2h$

According to the problem,

$\pi r^2 h=25$

$\Rightarrow h=\frac{25}{\pi r^2}$

The surface area of the base of the can is = $\pi r^2$

The metal for the bottom will cost $2.00 per cm²

The metal cost for the base is =$(2.00× $\pi r^2$ )

The lateral surface area of the can is = $2\pi rh$

The metal for the side will cost $1.25 per cm²

The metal cost for the base is =$(1.25× $2\pi rh$ )

$=\$2.5 \pi r h$

Total cost of metal is C= 2.00 $\pi r^2$ + $2.5 \pi r h$

Putting $h=\frac{25}{\pi r^2}$

$\therefore C=2\pi r^2+2.5 \pi r \times \frac{25}{\pi r^2}$

$\Rightarrow C=2\pi r^2+ \frac{62.5}{ r}$

Differentiating with respect to r

$C'=4\pi r- \frac{62.5}{ r^2}$

Again differentiating with respect to r

$C''=4\pi + \frac{125}{ r^3}$

To find the minimize cost, we set C'=0

$4\pi r- \frac{62.5}{ r^2}=0$

$\Rightarrow 4\pi r=\frac{62.5}{ r^2}$

$\Rightarrow r^3=\frac{62.5}{ 4\pi}$

⇒r=1.71

Now,

$\left C''\right|_{x=1.71}=4\pi +\frac{125}{1.71^3}>0$

When r=1.71 cm, the metal cost will be minimum.

Therefore,

$h=\frac{25}{\pi\times 1.71^2}$

⇒h=2.72 cm

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

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3 years ago

If you have 1 movie ticket of $7.50 . And the cost of 2 movie tickets are $15 . So what is the cost of 4 movies

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Since 2 movie tickets equal to $15 I am only left to assume we are adding $7.50 to every movie ticket, going by that logic

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