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Salsk061 [2.6K]
3 years ago
10

you toss a ball that travels on the path y= -0.1x^2 + 2x+4 where x and y are measured in meters. Sketch the path of the ball. Ho

w high does the ball go?

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
8 0

Answer:

The ball goes 14 meters high

Step-by-step explanation:

Given the function

y= -0.1x^2 + 2x + 4

In the figure attached, the function is shown.

The maximum height is equivalent to the vertex of the function, which is obtained as follows:

Xv = -b/(2a) = -2/(2*-0.1) = 10

Yv = -0.1Xv^2 + 2Xv + 4

Yv = -0.1(10)^2 + 2(10) + 4 = 14

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You're making this really tough on me.. I can just barely read the equations

I think it's  1+6x  and 7x-3  .  b/c they are the same length sides you can set those equal

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that worked out well :

for the tangent..   it's   Tan(Ф)= Opp/ Adj

but I don't know which side they want to solve for.. I think you may have left off some of the instructions????  :/

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or

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3)

x-2 = 2x-10

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again they made it work out easy :)

Then plug 8 into either equation to find the length of the tangent lines

8-2=10

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4) = 2)   ??? they are the same question  maybe  you meant to put something else?

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