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7nadin3 [17]
3 years ago
13

HELP ME PLEASE!!!!!!!!!

Mathematics
1 answer:
bixtya [17]3 years ago
6 0
Use Conects it got all the math questions n got the answer to questions ahead of the one u looking for
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The region r is enclosed by the curves y=4-4x2 and y=0
Misha Larkins [42]

The region r is enclosed by the curves y₁ = 4 - 4x² and y₂ = 0 is 16/3 or 5.333 square units.

<h3>What is an area bounded by the curve?</h3>

When the two curves intersect then they bound the region is known as the area bounded by the curve.

The region r is enclosed by the curves y₁ = 4 - 4x² and y₂ = 0

The intersection points will be

       y₁ = y₂

4 - 4x² = 0

        x = ±1

Then the area bounded by the curves will be

\rm Area = \int _{-1}^1 (y_1-  y_2) dx\\\\Area = \int _{-1}^1 (4 - 4x^2) dx\\\\Area = \left [ 4x  - \dfrac{4x^3}{3} \right ]_{-1}^1\\\\Area = 4 \left ( 1 + 1 \right ) - \dfrac{4}{3} \left ( 1^3 - (-1)^3 \right )\\\\Area = 8 - \dfrac{8}{3}\\\\Area = \dfrac{16}{3} = 5.333 \

More about the area bounded by the curve link is given below.

brainly.com/question/24563834

#SPJ4

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2 years ago
Find equivalent fraction for each given fractions.
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What are the given fractions to find 
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