What is the distance between the endpoints (2,3) and (-3,-2)?

Mathematics

1 answer:

Deffense [45]2 years ago

3 0

$distance= \sqrt{(-3-2)^2+(-2-3)^2}= \sqrt{25+25}= \sqrt{50}=5 \sqrt{2}$

Answer is 5√2

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Help 2,4+0,8=.......-0,06=........+1,21=.......+1,78=....-5,14=.

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Lets write this out:-

2.4 + 0.8 =______ - 0.06 = _____+ 1.21=_____+1.78=_____- 5.14=___

So to solve d blanks we will do d following:-

2.4 + 0.8 = 3.2

Now lets write this out AGAIN.

2.4 + 0.8 = 3.2 - 0.06 = _____+ 1.21=_____+1.78=_____- 5.14=___

Now lets solve again:-

3.2 - 0.06 = 3.14

Now lets write this out AGAIN.

2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21=_____+1.78=_____- 5.14=___

Now lets solve again:-

3.14 + 1.21= 4.25

Now lets write this out AGAIN.

2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21 = 4.25 +1.78=_____- 5.14=___

Now lets solve again:-

4.25 +1.78= 6.03

Now lets write this out AGAIN.

2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21 = 4.25 +1.78= 6.03 - 5.14=___

Now lets solve again:-

6.03 - 5.14 = 0.89

Now lets write this out AGAIN.

2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21 = 4.25 +1.78= 6.03 - 5.14= 0.89

So, 2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21 = 4.25 +1.78= 6.03 - 5.14= 0.89

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