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Vikki [24]
3 years ago
14

What is the distance between the endpoints (2,3) and (-3,-2)?

Mathematics
1 answer:
Deffense [45]3 years ago
3 0
distance= \sqrt{(-3-2)^2+(-2-3)^2}= \sqrt{25+25}= \sqrt{50}=5 \sqrt{2}

Answer is 5√2
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Describe the end behavior of the function f(x)=−8x4.
Maksim231197 [3]

Answer:

As x approaches infinity,  f(x) approaches negative infinity.

As x approaches negative infinity,  f(x) approaches negative infinity.

Step-by-step explanation:

5 0
3 years ago
What is the value of n in the equation -1.2(2n+4)+6=-9+4(2n+1)
Shalnov [3]

Answer:

n = 6.2/-10.4=0.5962

Step-by-step explanation:

What is the value of n in the equation. we would make n the subject formula -1.2(2n+4)+6=-9+4(2n+1)

Opening the brackets,

-1.2×2n -1.2×4 + 6= -9 +4×2n + 4×1

-2.4n -4.8 +6 = -9 +8n + 4

-2.4n -4.8 +6 = -9 + 4 + 8n= -5+8n

Collecting like terms

-2.4n-8n = -5+4.8-6

-10.4n =-6.2

n = -6.2/-10.4= 0.5962

Let's check, put n= 0.5962 in the equation

-2.4n -4.8 +6 = -9 +8n + 4

Lefthand side

-2.4×0.5962-4.8+6= -0.230

Right hand side

-9+ 8× 0.5962 +4

=-9 +4.7696 +4

=0.230

Right hand side = left hand side

4 0
3 years ago
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WILL<br><br><br><br><br> GIVE <br><br><br> BRAINLIST ANSWER
marta [7]

Answer:

22 is the range for the data set.

<h3>stay safe healthy and happy.</h3>

8 0
2 years ago
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Evaluate j/4<br> when j=12
Aleks04 [339]
I'm guessing, you substitute j with 12 and then you would have 12/4 and that would be 3
7 0
3 years ago
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Which expression is equivalent to x³ - x² - 14x + 24?
serg [7]

Answer:

<h3>A. ( x - 2 )( x - 3 )(x + 4 )</h3>

<h3>Step-by-step explanation:</h3>

<h3>x³ - x² - 14x + 24</h3>

<h3>1. Use the rational root theorem</h3>

= (x  - 2) \frac{x ^{3}  -x^{2}  - 14x + 24}{x - 2}

<h3>2. \frac{  {x}^{3} - {x}^{2}  - 14x + 24 }{x - 2}  =  {x}^{2}  + x - 12</h3><h3 />

= ( x - 2 )( x² + x - 12 )

<h3>3. Factor x² + x - 12 : ( x -3 )( x + 4)</h3>

= ( x - 2 )( x - 3 )(x + 4 )

<h3>Solution : </h3>

<h3>= ( x - 2 )( x - 3 )(x + 4 )</h3>
3 0
1 year ago
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