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Feliz [49]
2 years ago
5

Which expression is equivalent to x³ - x² - 14x + 24?

Mathematics
1 answer:
serg [7]2 years ago
3 0

Answer:

<h3>A. ( x - 2 )( x - 3 )(x + 4 )</h3>

<h3>Step-by-step explanation:</h3>

<h3>x³ - x² - 14x + 24</h3>

<h3>1. Use the rational root theorem</h3>

= (x  - 2) \frac{x ^{3}  -x^{2}  - 14x + 24}{x - 2}

<h3>2. \frac{  {x}^{3} - {x}^{2}  - 14x + 24 }{x - 2}  =  {x}^{2}  + x - 12</h3><h3 />

= ( x - 2 )( x² + x - 12 )

<h3>3. Factor x² + x - 12 : ( x -3 )( x + 4)</h3>

= ( x - 2 )( x - 3 )(x + 4 )

<h3>Solution : </h3>

<h3>= ( x - 2 )( x - 3 )(x + 4 )</h3>
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The formula for the volume of a pyramid is =13ℎ
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6 0
3 years ago
Fifty students in the seventh grade are trying to raise at least $2000 for sports supplies. They already raised $750. How much s
Vaselesa [24]

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Step-by-step explanation:

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4 0
3 years ago
For the polynomial function ƒ(x) = x4 −25x2, find the zeros. Then determine the multiplicity at each zero and state whether the
AfilCa [17]

<u>ANSWER</u>

The zeros are x=-5,x=0,x=5


EXPLANATION

Given;

f(x)=x^4-25x^2.


We can rewrite the function as


f(x)=x^2(x^2-25)


\Rightarrow f(x)=x^2(x^2-5^2)


\Rightarrow f(x)=x^2(x-5)(x+5)



The zeros are found by equating the function to zero.


\Rightarrow x^2(x-5)(x+5)=0


\Rightarrow (x-5)=0

The multiplicity is 1, since it is odd the graph crosses at this intercept. which is x=5


Or

\Rightarrow (x+5)=0


The multiplicity is 1, since it is odd the graph crosses at this intercept. which is x=-5


Or


\Rightarrow x^2=0


This last root has a multiplicity of 2.

That is

x=0 repeats two times.


Since the multiplicity is even, the graph touches the x-axis at the point x=0.



See graph.









5 0
3 years ago
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