Question

The altitude of an equilateral triangle is 6 units long. The length of one side of the triangle is ____ units.

Answer 1

Given:

height of the equilateral triangle = 6 units

Required:

Length of the side of an equilateral triangle.

Solution:

To solve the problem, we need to split the equilateral triangle into half. Know that the sum of all the angles in a triangle is 180°. Since, we know that each angle in a equilateral triangle is 60°, splitting it into half gives us a 30-60-90 triangle. 
The length of each side of a 30-60-90 triangle is as follows:
     1. The side opposite to the angle 30° is equal to x/2.
     2. The side opposite to the angle 60°, which is the altitude, is square root of 3 divided by 2.
     3. The side opposite to the angle 90°, which is the length of the side is equal to x.

Since we know the value of the altitude, we can equate its corresponding equation.

x√3/2 = 6
x = 6.9 units or approximately 7 units.

Answer 2

Answer:

The length of one side of the triangle is 4√3 units.

Step-by-step explanation:

If the length of sides is a units then the altitude of an equilateral triangle is

$h=\frac{\sqrt{3}}{2}a$

Let the length of one side of the triangle be x units.

$h=\frac{\sqrt{3}}{2}x$

It is given that the altitude of an equilateral triangle is 6 units long.

$6=\frac{\sqrt{3}}{2}x$

Multiply both sides by 2.

$12=\sqrt{3}x$

Divide both sides by √3.

$\frac{12}{\sqrt{3}}=x$

Rationalize the denominator.

$\frac{12}{\sqrt{3}}\times \frac{\sqrt{3}}{\sqrt{3}}=x$

$\frac{12\sqrt{3}}{3}=x$

$4\sqrt{3}=x$

The length of one side of the triangle is 4√3 units.

$x=4\sqrt{3}\approx 6.9282$

It can be written as 6.9282 units.