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MrRa [10]
3 years ago
12

the distance between Columbus Ohio and New York City is about 560 miles how many hours would it take the train to travel between

cities
Mathematics
2 answers:
arlik [135]3 years ago
7 0
How fast is the train going??
Zolol [24]3 years ago
7 0
<span>2144 miles in 8 hours. In 1 hour = 2144 / 8 = miles in 1 hour and that = 268</span>
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nevsk [136]
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Use this formula:

Area = ((a + b)/2) x h

a is the top length

b is the bottom length

h is the vertical height

1) Substitute in the values:

((3.8 + 6.2)/2) x 7 = 35ft^2 <== this is the answer

2) Substitute in the values:

((10.3 + 15.1)/2) x 12.6 = 160.02in^2 <== this is the answer

<h3><u>✽</u></h3>

➶ Hope This Helps You!

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3 0
3 years ago
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You have read 4 of the books shown. Which choice shows 2 ways of writing the fraction of these books that you read?
Olegator [25]
  • Total books read: 4
  • Total books in list: 12

So it can be shown as:

\sf \dfrac{read \ books}{total \ books \ in \ list}

\hookrightarrow \sf \dfrac{4}{12}

on simplifying

\hookrightarrow \sf \dfrac{1}{3}

So, option 1 is correct.

8 0
2 years ago
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Simplify the expression<br> (1 + 1/x)(1 - 2/x+1)(1 + 2/x-1)
valentinak56 [21]

Answer: 4(×+1) (×-1)

Step-by-step explanation:

3 0
2 years ago
DBE is obtained by enlarging ABC. If the area of ABC is 3 square units, what is the area of DBE?
Amanda [17]

Answer:

The area of DBE = 27 square units

Step-by-step explanation:

Area of ABC = 3 square units

In the figure, we can see that ABC was enlarged so that BDE is formed where side BD = 6 and AB was = 2

Hence ABC was enlarged 3 times its size.

We know by formula that:

Area of ABC = 1/2(base x perpendicular)

3 = 1/2(2 x p)

=> p = 3

As ABC was enlarged 3 times its size, the perpendicular of BDE must be 3*p

= 3*3 = 9

AREA OF DBE = 1/2(base*perp)

= 1/2(6*9)

= 27 square units

8 0
3 years ago
Look at the picture<br>​
Sonbull [250]

\large\displaystyle\text{$\begin{gathered}\sf 9|x-8| < 36 \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf Divide \ both \ sides \ by \ 9. \end{gathered}$}

  • \large\displaystyle\text{$\begin{gathered}\sf  \frac{9(|x-8|)}{9} < \frac{36}{9}   \end{gathered}$}
  • \large\displaystyle\text{$\begin{gathered}\sf |x-8| < 4 \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf Solve \ Absolute \ Value. \end{gathered}$}

  • \large\displaystyle\text{$\begin{gathered}\sf |x-8| < 4 \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf We \ know \ x-8 < 4 \ and \ x-8 > -4 \end{gathered}$}

<u>                                                                                                                             </u>

         \large\displaystyle\text{$\begin{gathered}\sf x-8 < 4 \ (Condition \ 1) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x-8+8 < 4+8 \ (Add \ 8 \ to \ both \ sides) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x < 12 \end{gathered}$}

<u>                                                                                                                             </u>

           \large\displaystyle\text{$\begin{gathered}\sf x-8 > -4 \ (Condition \ 2) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x-8+8 > -4+8 \ (Add \ 8 \ to \ both \ \ sides) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x > 4 \end{gathered}$}

<u>                                                                                                                             </u>

<u />\underline{\boldsymbol{\sf{Answer}}}

\boxed{\large\displaystyle\text{$\begin{gathered}\sf x < 12 \ and \ x > 4 \end{gathered}$} }

\large\displaystyle\text{$\begin{gathered}\sf Therefore,\bf{\underline{the \  correct \ option}} \  \end{gathered}$}\large\displaystyle\text{$\begin{gathered}\sf is \ \bf{\underline{"A"}}. \end{gathered}$}

6 0
2 years ago
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