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horsena [70]
3 years ago
6

find the common difference of the arithmetic sequence. 9, 13, 17, 21, . . . a. nine thirteenths b. 4 c. one and four ninths d. 2

2
Mathematics
1 answer:
shusha [124]3 years ago
3 0
The answer is letter b.4
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3 years ago
A multiple-choice standard test contains total of 25 questions, each with four answers. Assume that a student just guesses on ea
weqwewe [10]

Answer:

a)  8*88*10⁻⁶ ( 0.00088 %)

b) 0.2137 (21.37%)

Step-by-step explanation:

if the test contains 25 questions and each questions is independent of the others, then the random variable X= answer "x" questions correctly , has a binomial probability distribution. Then

P(X=x)= n!/((n-x)!*x!)*p^x*(1-p)^(n-x)

where

n= total number of questions= 25

p= probability of getting a question right = 1/4

then

a) P(x=n) = p^n = (1/4)²⁵ = 8*88*10⁻⁶ ( 0.00088 %)

b) P(x<5)= F(5)

where F(x) is the cumulative binomial probability distribution- Then from tables

P(x<5)= F(5)= 0.2137 (21.37%)

7 0
3 years ago
What is the value of the expression?
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Answer:

690

Step-by-step explanation:

(323+1715)-(1135+213)

(2038)-(1348)

=690

5 0
3 years ago
Jessica had 140 to spend on 8 books. After buying them she had 12 dollars. How much did each book cost?
Rashid [163]

Answer:

each book was $16

Step-by-step explanation:

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hope this helps!

8 0
3 years ago
What is the form of the Pythagorean triple generator?​
stepladder [879]

Answer:(x^2+y^2)^2=(x^2+y^2)(x^2+y^2)

Step-by-step explanation:

We can rewrite left side into right side form

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we can expand it

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we can add and subtract 2x^2y^2

(x^2+y^2)^2=x^4+y^4+2x^2y^2+2x^2y^2-2x^2y^2

(x^2+y^2)^2=x^4-2x^2y^2+y^4+2x^2y^2+2x^2y^2

(x^2+y^2)^2=x^4-2x^2y^2+y^4+4x^2y^2

(x^2+y^2)^2=x^4-2x^2y^2+y^4+(2xy)^2

(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2

4 0
3 years ago
Read 2 more answers
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