find the common difference of the arithmetic sequence. 9, 13, 17, 21, . . . a. nine thirteenths b. 4 c. one and four ninths d. 2
1 answer:
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Answer:
=
+ 6
Step-by-step explanation:
The terms have a common difference d between consecutive terms, that is
10 - 4 = 16 - 10 = 22 - 16 = 6
To obtain the next term add 6 to the previous term ( recursive rule ), thus
=
+ 6 with a₁ = 4
I hope this helps you
