Answer:
1 in =4 ft
Step-by-step explanation:
Divide 32by 8 and 40 by 10
Answer:
d. 1.5%
Step-by-step explanation:
Given - The track and field coach records Ian's 400-meter race times during three practices.
Practice 1 2 3
Time (s) 63 60 58
To find - How much greater was the percent of change from Practice 1 to Practice 2 than from Practice 2 to Practice 3? Round to the nearest tenth.
a.
7.9%
b. 4.8%
c. 3.3%
d. 1.5%
Proof -
% change from Practice 1 to Practice 2 change =
%
=
% = - 4.761904762 %
⇒% change from Practice 1 to Practice 2 change = - 4.762 %
Now,
% change from Practice 2 to Practice 3 change =
%
=
% = - 3.334 %
⇒% change from Practice 2 to Practice 3 change = - 3.3334 %
So,
- 4.461904762% - (- 3.3334%) = -4.461904762 + 3.3334 % = -1.4285 % ≈ 1.5%
∴ we get
Value = 1.5%
The correct option is - d. 1.5%
in this problem we have a vertical line
The equation of a vertical line is equal to the x-coordinate of the point that passes through it
so
in this case
the equation of the line is
x=-1
Well you could multiply 432 by 0.75, or you can divide it by 4 and then multiply it by 3. Either way your answer is 324.
The relationship between wavelength and frequency is expressed by the equation λν=c where λ is the wavelength, v is the frequency and c is the speed of light which has a value of 3x10^8 m/s.
λν=c
λ(3 × 10^9)= 3x10^8
λ = 0.1 m
Hope this answers the question.