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MArishka [77]
3 years ago
11

Find the exact value of sin (o)

Mathematics
1 answer:
Yuliya22 [10]3 years ago
3 0
The best way to think about this value is to picture the graph of the "normal" sin wave.  One period starts at (0, 0), goes up to a y value of 1 at an x value of \frac{ \pi }{2},  goes back down to a y value of 0 at x = \pi, goes down to a y value of -1 at x = \frac{3 \pi }{2} and ends up completing one period at a y value of 0 and an x value of 2 \pi.  We can see from that what the sin ratios are at each one of those x values.  When x = 0, y = 0, so the sin of 0 is 0.  Check your calculator to see that this is true, but understanding the graph tells you WHY it is true.
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Average rate of change for f(x) = x2 − 3x − 10 from x = −5 to x = 10.
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The average rate of change is the slope of the secant line connecting the points on f(x) from x=-5 to x=10.

In other words, it is just the slope of the straight line connecting the points
(-5,f(-5)) \: and \: (10,f(10))

So we were given ,

f(x) = {x}^{2} - 3x - 10

At
x = - 5
f( - 5) = {( -5 )}^{2} - 3( - 5) - 10
f( - 5) = 25 + 15- 10
f( - 5) = 30

Also at
x = 10
f( 10) = {( 10)}^{2} - 3( 10) - 10.
f( 10) = 100- 30 - 10
f( 10) = 60

The average rate of change
= \frac{f(10) - f( - 5)}{10 - - 5}
= \frac{60- 30}{15}
= \frac{30}{15}
= 2
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Answer:

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Step-by-step explanation:

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