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4 years ago

9

PROBLEM SOLVING AND APPLICATION

1 answer:

Helga [31]4 years ago

4 0

2 out of 15 for both

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(20 points) In the month of September, the bird population increased by a factor of 1.25 every day for those 30 days. The functi

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Answer:

0 ≤ x ≤ 30

Step-by-step explanation:

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3 years ago

Is Figure ABCD congruent to Figure PQRS? Use the drop-down menus to explain your answer. у 6 В. R 4 S a Q N A I Р 8 -6 -4 -2 O -

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are not and does not

Step-by-step explanation:

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2 years ago

The wheels on Noah's bike have a circumference of about 5 feet. How far does the bike travel as the wheels makes 15 complete rot

grin007 [14]

Answer:

75 feet

Step-by-step explanation:

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3 years ago

Read 2 more answers

A CAT scan produces equally spaced cross-sectional views of a human organ that provide information about the organ otherwise obt

Andrew [12]

Answer:

$V \approx 1113$

Step-by-step explanation:

Here we have

Space $x$ in cm Area in square centimeters - $A(x)$

$x = 0$ $0$
$x = 1.5$ 19
$x = 3$ 58
$x = 4.5$ 78
$x = 6$ 94
$x = 7.5$ 105
$x = 9$ 117
$x = 10.5$ 129
$x = 12$ 62
$x = 13.5$ 40
$x=15$ 0

As we can see, $0 \leq x \leq 15$ and we need to divide it into 5 subintervals, where

$\Delta x = \frac{15-0}{5} = 3$

is the length of each interval. Therefore, the subintervals are

$[0,3], [3,6], [6,9], [9,12], [12,15]$

The midpoint of the first interval is calculated as

$x^*_1 = \frac{3+0 }{2} = 1.5$

Similarly, we obtain that the midpoints of other subintervals are

$x^*_2 =4.5, x^*_3= 7.5, x^*_4= 10.5, x^*_5 = 13.5$

By the Midpoint rule, we have

$V \approx \sum_{i=1}^{5} A(x^*_i) \Delta x \\\\\phantom{V} = \Delta x (A(1.5) + A(4.5) + A(7.5) + A(10.5)+ A(13.5))$

From the given data above, we have

$A(1.5) = 19, A(4.5) = 78, A(7.5) = 105, A(10.5) = 129, A(13.5) = 40$

Therefore,

$V \approx 3 (19+ 78+ 105+129+40 ) =$ $1113$

8 0

4 years ago

P(2,3); y-4=-2(x+3) perpendicular

snow_tiger [21]

Y=-2x-6+4
Y=-2x-2
Because -1=-2*(1/2)
So y=(1/2)x-2
3=(1/2)*2+b
b=2
So (1/2)x+2

7 0

3 years ago