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Aleksandr [31]
3 years ago
11

What's the quadratic formula?

Mathematics
1 answer:
lesantik [10]3 years ago
6 0
<span>The quadratic formula is the solution of the quadratic equation. There's other ways to solve it, but the quadratic formula the easiest/most convenient.


</span>

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Omg!? Is 96 correct??
nlexa [21]
If you are finding the perimeter I believe you would just add up the four sides, getting 46
5 0
2 years ago
WILL MARK BRAINILEST!
Andru [333]
So it started at 180. After 4 more years it’s grown 188 cm to 368. If we estimate that it’ll grow 188 cm in another 4 years that puts our total to around 556. If we estimate and take off a year, it would probably be around 548 cm :)
8 0
2 years ago
Correct I’ll give brainlist no links or I’ll report
Vera_Pavlovna [14]

Answer:

y = 8x - 64

Step-by-step explanation:

Start with y = mx + b, the slope-intercept equation.  Replace m with 8, x with 7 and y with -8:

-8 = 8(7) + b, or

-8 - 56 + b, or

b = -64

Then the desired equation is

y = 8x - 64

3 0
3 years ago
A triangle with sides 11m , 13m and 18m is a right triangle.<br> ​<br> A<br> True<br> B<br> False
Julli [10]

\bold{\huge{\pink{\underline{ Solution}}}}

\bold{\underline{ Given :-}}

  • <u>A </u><u>triangle </u><u>with </u><u>sides </u><u>11m</u><u>, </u><u> </u><u>13m </u><u>and </u><u>18m</u>

\bold{\underline{ To \: Find :-}}

  • <u>We</u><u> </u><u>have </u><u>to </u><u>check </u><u>it </u><u>whether </u><u>it </u><u>is </u><u>right </u><u>angled </u><u>triangle </u><u>or </u><u>not</u><u>? </u>

\bold{\underline{ Let's \: Begin :-}}

\sf{\red{ In \:right \:angled\ : triangle, }}

According to the Pythagoras theorem, The sum of the squares of perpendicular height and the square of the base of the triangle is equal to the square of hypotenuse that is sum of the squares of two small sides equal to the square of longest side of the triangle.

<u>We </u><u>imply</u><u> </u><u>it </u><u>in </u><u>the </u><u>given </u><u>triangle </u><u>,</u>

\sf{\red{ ( Perpendicular)² + (Base)² = (Hypotenuse)²}}

\sf{(AB)² + (BC)² = (AC)²}

\sf{ (11)² + (13)² = (18)² }

\sf{ 121 + 169 ≠  324 }

\sf{ 290 ≠ 324  }

<u>From </u><u>Above </u><u>we </u><u>can </u><u>conclude </u><u>that</u><u>, </u>

The sum of the squares of two small sides that is perpendicular height and base is not equal to the square of longest side that is Hypotenuse

\sf{\blue{ Hence,\: Your\: answer \:is \:false }}

5 0
2 years ago
(x – 4)2 = -9 has no real solution
Keith_Richards [23]

Answer:

x = -1/2

Step-by-step explanation:

(x - 4) * 2 = -9

Divide both sides by 2:

x - 4 = - 9 / 2

Add 4 to both sides:

x = - 1 / 2.

5 0
2 years ago
Read 2 more answers
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