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Anna11 [10]
3 years ago
12

What is the point of intersection when the system of equations below is graphed on the coordinate plane?

Mathematics
1 answer:
lesantik [10]3 years ago
4 0
Multiply the first equation by -2 gives:_
-2y = -8 + 2x

2y = 8 - 2x

adding these 2 equations:-

0 = 0

This shows that the 2 equations are  equal so there are infinite solutions


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You borrow ​$600 from a friend the first week and pay the friend back ​$20 each week there after. Write the first six terms in t
d1i1m1o1n [39]
1st term: 20 dollars
 2nd term:40 dollars
3rd term: 60 dollars
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5th term:100 dollars
6th term:120 dollars
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6 0
3 years ago
What is the answer to 4x+y=10
Alina [70]

Answer:

y = -4x + 10

Step-by-step explanation:

I am going to assume you are trying to write the equation of a line.

4x + y = 10

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y = -4x + 10

7 0
3 years ago
What’s 5000÷4x8÷3x20?
PilotLPTM [1.2K]

Answer:

1250  3  x28

Step-by-step explanation:

5000

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3

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4 0
3 years ago
Read 2 more answers
When solving the system using the additional/elimination method, which variables will cancel?
iogann1982 [59]

Answer:

the x terms

Step-by-step explanation:

there is a +x and a -x.

x-x=0,

x will cancel out

6 0
3 years ago
A survey of an urban university (population of 25,450) showed that 870 of 1,100 students sampled supported a fee increase to fun
Katen [24]

Answer:

95% confidence interval for the proportion of students supporting the fee increase is [0.767, 0.815]. Option C

Step-by-step explanation:

The confidence interval for a proportion is given as [p +/- margin of error (E)]

p is sample proportion = 870/1,100 = 0.791

n is sample size = 1,100

confidence level (C) = 95% = 0.95

significance level = 1 - C = 1 - 0.95 = 0.05 = 5%

critical value (z) at 5% significance level is 1.96.

E = z × sqrt[p(1-p) ÷ n] = 1.96 × sqrt[0.791(1-0.791) ÷ 1,100] = 1.96 × 0.0123 = 0.024

Lower limit of proportion = p - E = 0.791 - 0.024 = 0.767

Upper limit of proportion = p + E = 0.791 + 0.024 = 0.815

95% confidence interval for the proportion of students supporting the fee increase is between a lower limit of 0.767 and an upper limit of 0.815.

5 0
3 years ago
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