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adoni [48]
3 years ago
9

Can somebody please help me

Mathematics
2 answers:
Furkat [3]3 years ago
5 0

Answer:

7

Step-by-step explanation:

9-\frac{8}{S} \\S=4

Substitute the value of S into the expression:

9-\frac{8}{4}

Simplify the fraction by dividing the numerator and denominator by 4:

9-\frac{8/4}{4/4} \\\\9-\frac{2}{1}

Simplify :

9-2

Solve with subtraction:

9-2=7

Finito.

Aleksandr-060686 [28]3 years ago
3 0

Answer:

5s-8 = 0  

Add  8  to both sides of the equation :  

                     5s = 8

Divide both sides of the equation by 5:

                    s = 8/5 = 1.600

Step-by-step explanation:

it was difficult and too much wording

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A manufacturer produces light bulbs that have a mean life of at least 500 hours when the production process is working properly.
denpristay [2]

Answer:

We conclude that the population mean light bulb life is at least 500 hours at the significance level of 0.01.

Step-by-step explanation:

We are given that a manufacturer produces light bulbs that have a mean life of at least 500 hours when the production process is working properly. The population standard deviation is 50 hours and the light bulb life is normally distributed.

You select a sample of 100 light bulbs and find mean bulb life is 490 hours.

Let \mu = <u><em>population mean light bulb life.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 500 hours      {means that the population mean light bulb life is at least 500 hours}

Alternate Hypothesis, H_A : \mu < 500 hours     {means that the population mean light bulb life is below 500 hours}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;

                           T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean bulb life = 490 hours

           σ = population standard deviation = 50 hours

           n = sample of light bulbs = 100

So, <u><em>the test statistics</em></u>  =  \frac{490-500}{\frac{50}{\sqrt{100} } }

                                     =  -2

The value of z test statistics is -2.

<u>Now, at 0.01 significance level the z table gives critical value of -2.33 for left-tailed test.</u>

Since our test statistic is higher than the critical value of z as -2 > -2.33, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis.</u>

Therefore, we conclude that the population mean light bulb life is at least 500 hours.

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